Consider a problem being solved using Buckingham's theorem, and involving the five physical quantities s, t, u, v and w (what exactly they are, is not needed to solve this problem). The dimensions of these quantities are: [s] = M² L³T [t] = M LT? [u] = T3 [v] = L²T (w] = M? Suppose we would like to use Buckingham's theorem to develop a mathematical model for t in terms of s, u, v and w. We consider dimensionless product(s) of the form: In the process of finding dimensionless product(s) for this problem, one of the equations (in terms of a, b, c, d and e) we arrive at is: Оа+ 2b + Зс — d — 0 O -a + 26 + 3c+d =0 - O None of the other options are correct. Oa + 26 + 3c+d = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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Consider a problem being solved using Buckingham's theorem, and involving the five physical
quantities s, t, u, v and w (what exactly they are, is not needed to solve this problem).
The dimensions of these quantities are:
[s] = M²L³T
[t] = M LT
[u] = T3
[v] = L?T
[w] = M?
Suppose we would like to use Buckingham's theorem to develop a mathematical model for t in terms
of s, u, v and w. We consider dimensionless product(s) of the form:
In the process of finding dimensionless product(s) for this problem, one of the equations (in terms of
a, b, c, d and e) we arrive at is:
Оa+26 + Зс — d — 0
—а + 2b + Зс + d — 0
None of the other options are correct.
Oa + 2b + 3c +d= 0
Transcribed Image Text:Consider a problem being solved using Buckingham's theorem, and involving the five physical quantities s, t, u, v and w (what exactly they are, is not needed to solve this problem). The dimensions of these quantities are: [s] = M²L³T [t] = M LT [u] = T3 [v] = L?T [w] = M? Suppose we would like to use Buckingham's theorem to develop a mathematical model for t in terms of s, u, v and w. We consider dimensionless product(s) of the form: In the process of finding dimensionless product(s) for this problem, one of the equations (in terms of a, b, c, d and e) we arrive at is: Оa+26 + Зс — d — 0 —а + 2b + Зс + d — 0 None of the other options are correct. Oa + 2b + 3c +d= 0
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