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Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis.    Find the equations of motion in terms of x.  Select all that apply.

Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis.    Find the equations of motion in terms of x.  Select all that apply.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis. 

 

Find the equations of motion in terms of x.  Select all that apply.
Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis. R m1 Find the equations of motion in terms of x. Select all that apply. Selected Answers: O [None Given] Answers: (4m1 + m, + |/ R2) dx (t) +2kx = 2m1g +m2g dt? d²x (t) (4m1 + |/R2) dt? + kx = 2m1g +m2g d?x(t) (m1+ 4m2 + 1/ R?)- dt? + 2kx = - (m1g + 2m2g) d²x (t) + kx = - (2m1g +m2g) dt? (4m1 + m2 + 1/ R²) (4m1 + m2 + 1/ R?) dʻx(t) dt? + 4kx = m1g +2m2g d?x (t) + kx = 2m1g + m2g dt? (4m1 + m2 + 1/ R²)
Transcribed Image Text:Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis. R m1 Find the equations of motion in terms of x. Select all that apply. Selected Answers: O [None Given] Answers: (4m1 + m, + |/ R2) dx (t) +2kx = 2m1g +m2g dt? d²x (t) (4m1 + |/R2) dt? + kx = 2m1g +m2g d?x(t) (m1+ 4m2 + 1/ R?)- dt? + 2kx = - (m1g + 2m2g) d²x (t) + kx = - (2m1g +m2g) dt? (4m1 + m2 + 1/ R²) (4m1 + m2 + 1/ R?) dʻx(t) dt? + 4kx = m1g +2m2g d?x (t) + kx = 2m1g + m2g dt? (4m1 + m2 + 1/ R²)
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