Consider a signal v(t) = b(t)cos²(@ot + 0). As in the figure, b(t) = b, for t € ((k - 1)T.KTB) and Dx= 1,-1,-1,1 for k = 1,2,3,4 with 1/T, « fo. v(t) passes through an integrator that takes integration on v(t) for every Tp seconds and outputs v.(kT,) for k = 1,2,3,4. Determine va (kT,) for k = 1,2,3,4 with your derivations. 5. %3! %3D %3D b(t) 1. -1 -1 4 t(T) 3 2.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Consider a signal v(t) = b(t)cos? (@gt + 0). As in the figure, b(t) = by fort E (k - 1)Tp,kTbl and Dk
1,-1,-1,1 fork = 1,2,3, 4 with 1/T, « fo. v(t) passes through an integrator that takes integration on Deion
every Th seconds and outputs vo(kT,) fork = 1.2. 3.4. Determine vo(kT) for k = 1,2,3,4 with your derivations.
5.
%3D
%3D
b(t) .
1.
-1
-1
1
4
t(Tp)
2
Transcribed Image Text:Consider a signal v(t) = b(t)cos? (@gt + 0). As in the figure, b(t) = by fort E (k - 1)Tp,kTbl and Dk 1,-1,-1,1 fork = 1,2,3, 4 with 1/T, « fo. v(t) passes through an integrator that takes integration on Deion every Th seconds and outputs vo(kT,) fork = 1.2. 3.4. Determine vo(kT) for k = 1,2,3,4 with your derivations. 5. %3D %3D b(t) . 1. -1 -1 1 4 t(Tp) 2
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