Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous. The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal recessive mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS Parental cross: Mother with wild type phenotype, Father with disease phenotype. Table 1. F1 DATA Gender Phenotype Disease Wild-type Male 0 23 Female 0 28 Table 2. F2 DATA Gender Phenotype Disease Wild-type Male 4 25 Female 7 15 Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous. The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal recessive mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS Parental cross: Mother with wild type phenotype, Father with disease phenotype. Table 1. F1 DATA Gender Phenotype Disease Wild-type Male 0 23 Female 0 28 Table 2. F2 DATA Gender Phenotype Disease Wild-type Male 4 25 Female 7 15 Choices- Do not reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test p-value is > 0.05. Do not reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test p-value < 0.005. Reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; the true mode of inheritance is X-linked recessive. Reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test < 0.05. Reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test > 0.05

Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous. The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal recessive mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS Parental cross: Mother with wild type phenotype, Father with disease phenotype. Table 1. F1 DATA Gender Phenotype Disease Wild-type Male 0 23 Female 0 28 Table 2. F2 DATA Gender Phenotype Disease Wild-type Male 4 25 Female 7 15 Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous. The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal recessive mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS Parental cross: Mother with wild type phenotype, Father with disease phenotype. Table 1. F1 DATA Gender Phenotype Disease Wild-type Male 0 23 Female 0 28 Table 2. F2 DATA Gender Phenotype Disease Wild-type Male 4 25 Female 7 15 Choices- Do not reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test p-value is > 0.05. Do not reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test p-value < 0.005. Reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; the true mode of inheritance is X-linked recessive. Reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test < 0.05. Reject the null hypothesis that the F2 data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test > 0.05

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 8CR

See similar textbooks

Related questions

Question

Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous.

The counts of the F₁ offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F₂ individuals. If you test the F₂ counts to determine whether they are consistent with an autosomal recessive mode of inheritance, what is your decision? Use a 0.05 significance level.

PARENTAL CROSS

Parental cross: Mother with wild type phenotype, Father with disease phenotype.

Table 1. F1 DATA

Gender	Phenotype
Disease	Wild-type
Male	0	23
Female	0	28

Table 2. F2 DATA

Gender	Phenotype
Disease	Wild-type
Male	4	25
Female	7	15

Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous.

PARENTAL CROSS

Parental cross: Mother with wild type phenotype, Father with disease phenotype.

Table 1. F1 DATA

Gender	Phenotype
Disease	Wild-type
Male	0	23
Female	0	28

Table 2. F2 DATA

Gender	Phenotype
Disease	Wild-type
Male	4	25
Female	7	15

Choices-

Do not reject the null hypothesis that the F₂ data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test p-value is > 0.05.

Do not reject the null hypothesis that the F₂ data are consistent with an autosomal recessive mode of inheritance; chi-square goodness of fit test p-value < 0.005.

Reject the null hypothesis that the F₂ data are consistent with an autosomal recessive mode of inheritance; the true mode of inheritance is X-linked recessive.

Reject the null hypothesis that the F₂ data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test < 0.05.

Reject the null hypothesis that the F₂ data are consistent with an autosomal recessive mode of inheritance; the p-value for the chi-square goodness of fit test > 0.05

Definition Definition Measure of central tendency that is the value that occurs most frequently in a data set. A data set may have more than one mode if multiple categories repeat an equal number of times. For example, in a data set with five item—3, 5, 5, 29, 473—the mode is 5 because it occurs twice and no other value occurs more than once. On a histogram or bar chart, the element with the highest bar represents the mode. Therefore, the mode is sometimes considered the most popular option. The mode is useful for nominal or categorical data (e.g., the most common color car that users purchase), but it is problematic for continuous data because it is more likely not to have any value that is more frequent than the other.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here