Consider circuit of Figure 9. The synthesized frequency generator produces2-kHz sinewave with amplitude 2.0 V. Identify the DC component of vR and theamplitude of the AC component of vR. You should assume that the capacitorbe modeled as a short circuit to an AC signal. The capacitormodeled as an open circuit to a DC signalExercise:аcanalways becan0.2 uF2 V50 kQVRSynthesizedFrequencyGeneratorFigure 9: Circuit with a DC and AC voltage sources, capacitor, and resistorw

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Asked Sep 17, 2019
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Consider circuit of Figure 9. The synthesized frequency generator produces
2-kHz sinewave with amplitude 2.0 V. Identify the DC component of vR and the
amplitude of the AC component of vR. You should assume that the capacitor
be modeled as a short circuit to an AC signal. The capacitor
modeled as an open circuit to a DC signal
Exercise:
а
can
always be
can
0.2 uF
2 V
50 kQ
VR
Synthesized
Frequency
Generator
Figure 9: Circuit with a DC and AC voltage sources, capacitor, and resistor
w
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Consider circuit of Figure 9. The synthesized frequency generator produces 2-kHz sinewave with amplitude 2.0 V. Identify the DC component of vR and the amplitude of the AC component of vR. You should assume that the capacitor be modeled as a short circuit to an AC signal. The capacitor modeled as an open circuit to a DC signal Exercise: а can always be can 0.2 uF 2 V 50 kQ VR Synthesized Frequency Generator Figure 9: Circuit with a DC and AC voltage sources, capacitor, and resistor w

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Step 1

Assume, output of synthesized frequency generator is V(t).

Synthesized frequency generator produces a sinewave signal having amplitude 2V and frequency 2KHz.

So,

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V( t)=2sin(4000Tt

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Step 2

In given circuit, AC and DC both voltage source is present so that using superposition Theorem in circuit.

Superposition theorem states that in a linear, bilateral ,active network if two or more than two independent sources are present then response in any branch of network would be algebraic sum of all responses produced by each independent source acting individually and other voltage source should short circuited and current source should open circuited.

Now, First take A.C source as it is and D.C source shorted.

Capacitor is also shorted because it is mentioned in question that capacitor should be shorted for A.C signal.

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50 kn VR Synthesized V(t) =Frequency Generator Resistor is in parallel with V(t) so that V=V(t)=2sin(4000nt) So.Amplitude ofAC component of V is 2V.

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Step 3

Now, Take D.C source as it is and A.C source shorted.

Capacitor is open because it is men...

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2 V 50 k VR Circuit is open so V -0V DC component of V, is OV

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