Consider the circuit below. The capacitor has 36 pF capacitance. R1 has 143 k Ω of resistance and R2 has 261 k Ω of resistance. The battery outputs 20 V. The switch has been in the closed position for a long time (long enough to fully charge the capacitor). At t = 0 s, the switch is opened (in the image below, the switch is open). Calculate the charge on the positive capacitor plate at t = 3,492 ns, in units of pC.
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Please round your answer to the fourth decimal place - I.e. 14.3325
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