CONSIDER THE CIRCUIT OF FIGURE 1, CONSIDERING THAT THE SWITCH SPENT A LONG TIME AT 1 AND WAS MOVED TO POSITION 2 AT THE INSTANT OF TIME EQUAL TOT = 0. DETERMINE: A) THE EQUATION OF THE CAPACITOR VOLTAGE AS A FUNCTION OF TIME (SWITCH IN POSITION 2). B) THE EQUATION OF ICT) (CURRENT IN RESISTOR R2) AS A FUNCTION OF TIME. C) IS ICT) A CONTINUOUS FUNCTION? JUSTIFY YOUR ANSWER. t = 0 R v(t) i(1) 6 kN 20 | R2 3 kN 12 v (* )Vs 100 μF FIGURE 1

CONSIDER THE CIRCUIT OF FIGURE 1, CONSIDERING THAT THE SWITCH SPENT A LONG TIME AT 1 AND WAS MOVED TO POSITION 2 AT THE INSTANT OF TIME EQUAL TOT = 0. DETERMINE: A) THE EQUATION OF THE CAPACITOR VOLTAGE AS A FUNCTION OF TIME (SWITCH IN POSITION 2). B) THE EQUATION OF ICT) (CURRENT IN RESISTOR R2) AS A FUNCTION OF TIME. C) IS ICT) A CONTINUOUS FUNCTION? JUSTIFY YOUR ANSWER. t = 0 R v(t) i(1) 6 kN 20 | R2 3 kN 12 v (* )Vs 100 μF FIGURE 1

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.27P

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From the given circuit. Switch S1 is in position A switch S2 is open. Both switches are in these states for a very long time. At t=0, switch S1 moves from position A to B while switch S2 remains open. 10ms after switch S1 moves to position B, switch S2 is closed and remains closed for 20ms only. ANSWER THE FOLLOWING: a.) Expression for the inductor current for 0 ≤ ? < 10??b.) Expression for the inductor current for 10?? ≤ ? < 30?? and 30?? ≤ ? < ∞c.) What is the time (in ms) after switch S1 moves to position B is the current in the inductor equivalent to 30% of the initial value (at ?=0).
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The circuit shown in Figure-2 is at steady state before the switch closes at time t = 0. The input to the circuit is the voltage of the voltage source, 12 V. The output of this circuit is the voltage across the capacitor, v(t). -Use Matlab Simscape Electrical to build and plot the output, v(t), as a function of t (by using scope). Use the plot to obtain an analytic representation of v(t) for t > 0. Hint: We expect v(t) = A + Be–t/τ for t > 0, where A, B, and τ are constants to be determined. Modify the circuit given in this example (build figure-2) https://www.mathworks.com/help/physmod/simscape/ug/operating-point-rlc-transient-response.html You will obtain a graph as figure 2-b and by using graph and substituting three ‘t’ values to v(t) then you can find A, B and τ.