b)01 #)Consider the common-emitter BJT amplifier circuit shown in Figure, QlaVcc=15V.8-150, V 0.7V.RE01K2, Rc = 4.7 km₂,R₁ = 17 k, R₂ = 10 kn, R = 47 kn, Rg 100 2.Assume7/2Votp/2R₁ifSkQwwwFigure Q1.a(i) Determine the values of Ic and Vce at the Q-point.(ii) Draw the AC equivalent circuit by considering the capacitors as short-circuited and determine the values of To, n. 9m. Assume early voltageis .(iii)Determine voltage gain, (vo/v).5 KMR₂2Differential amplifier shown in Figure Q1.b uses transistors with B = 100.Determine(i) The differential input resistance Rid.(ii) The overall differential voltage gain vod/Vsig (neglect the effectof To)B₁Re = 10 kZRQ₁t+15 VR₁R₁2= 1500Re 10 knB₂R₁ = 150 Ω= I MA

Since you have posted the multiple questions so we are supposed to answer the 1st one.

Consider the common-emitter 135T amplifier circuit shown in Figure, Ola Vce-15V, 0-150, VE 0.7V, RE- 1 k0, Rc = 4.7 ksz, R₁ - 47 KL, R₂ = 10 kn, R, 47 kn, R, 100 2. Assume ww R₁ is co. iii)Determine voltage gain, (vo/v₂). Re = R₁ Figure Q1.a (i) Determine the values of Ic and Vce at the Q-point. (ii) Draw the AC equivalent circuit by considering the capacitors as short- circuited and determine the values of To, Tn9m. Assume early voltage 192 Digura 1 buses transistoranid

Consider the common-emitter 135T amplifier circuit shown in Figure, Ola Vce-15V, 0-150, VE 0.7V, RE- 1 k0, Rc = 4.7 ksz, R₁ - 47 KL, R₂ = 10 kn, R, 47 kn, R, 100 2. Assume ww R₁ is co. iii)Determine voltage gain, (vo/v₂). Re = R₁ Figure Q1.a (i) Determine the values of Ic and Vce at the Q-point. (ii) Draw the AC equivalent circuit by considering the capacitors as short- circuited and determine the values of To, Tn9m. Assume early voltage 192 Digura 1 buses transistoranid

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter25: Television, Telephone, And Low-voltage Signal Systems

Section25.1: Television Circuit

Problem 5R: From a cost standpoint, which system is more economical to install: a master amplifier distribution...

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