Consider the curve segments: 1 $1: y = x from x = to x = 4 and 3 1 S2: y = Vxfrom x = -to x = 16. Set up integrals that give the arc lengths of the curve segments by integrating with respect to y. The length of the first segment is L, /1 + 4y² dy and the length of the second segment is L2 -dy. + 2y 16 4 The length of the fırst segment is LI +dy and the length of the second segment is L2 /V1+ 4y°dy. 16 1 -dy and the length of the second segment is L2 = /- / VI+ 4y° dy. The length of the first segment is LI 16 1 The length of the first segment is Lj = / v I + 2ydy and the length of the second segment is L2 2y 16 1 The length of the first segment is L, I + 2ydy and the length of the second segment is L2 1 + -dy. 2y

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