Consider the curve segments: S1: y = x from x = 1 to x = 2 and 1 S2: y = Vx from x =to x = 4. Set up integrals that give the arc lengths of the curve segments by integrating with respect to y. 1 -dy and the length of the second segment is L2 = 4y /Vi+ 4y°dy. The length of the first segment is L¡ = 2. 2 The length of the first segment is L¡ = IV1+ 4y?dy and the length of the second segment is L2 = 1 1+dy. 2. I+dy and the length of the second segment is L2 = 4y V1+4y°dy. The length of the first segment is LĮ The length of the first segment is L¡ = VI + 2ydy and the length of the second segment is L2 = 2y 4 1 1+dy. 2y The length of the first segment is L¡ = | VI+2ydy and the length of the second segment is L2 =

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