Consider the device shown below operating at steady-state using steam as the fluid. For every kg of steam that has flown, 500 kJ of work is done by the device. Calculate the ideal work, the thermodynamic efficiency of the device, and the lost work for every kg of steam that has flown. Neglect potential energy changes. P1 = 3 MPa T1 = 400 °C W° /m = 500 kJ/kg V1 = 160 m/s Turbine T2 = 100 °C V2 = 100 m/s Tb = 350 K Sat. vapor

Elements Of Electromagnetics
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Consider the device shown below operating at steady-state using steam as the fluid. For every
kg of steam that has flown, 500 kJ of work is done by the device. Calculate the ideal work, the
thermodynamic efficiency of the device, and the lost work for every kg of steam that has flown.
Neglect potential energy changes.
P1 = 3 MPa
T1 = 400 °C
W° /m = 500 kJ/kg
%3D
V1 = 160 m/s
Turbine
T2 = 100 °C
V2 = 100 m/s
Ть 3 350 К
Sat. vapor
Transcribed Image Text:Consider the device shown below operating at steady-state using steam as the fluid. For every kg of steam that has flown, 500 kJ of work is done by the device. Calculate the ideal work, the thermodynamic efficiency of the device, and the lost work for every kg of steam that has flown. Neglect potential energy changes. P1 = 3 MPa T1 = 400 °C W° /m = 500 kJ/kg %3D V1 = 160 m/s Turbine T2 = 100 °C V2 = 100 m/s Ть 3 350 К Sat. vapor
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