Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. Suppose the initial value of the sequence number is 111 and every segment sent to the receiver each contains 194 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. And every segment needs to be acknowledged. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but one of the ACKS is lost. Assume there are no timeouts and any out of order segments received are thrown out. TCP sender TCP receiver t= 1 t = 2 data segment t= 3 data segment> t= 4 data segment > t= 5 data segment > data segment >* t= 8 t = 9 t = 10 = 11 *ACK segment ACK segment t= 12 ACK segment t= 15 ACK segment t= 16 t= 17

Computer Networking: A Top-Down Approach (7th Edition)
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Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost.
Suppose the initial value of the sequence number is 111 and every segment sent to the receiver each contains 194 bytes.
The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for
this segment arrives at t = 15. And every segment needs to be acknowledged. As shown in the figure, 1 of the 5 segments is lost
between the sender and the receiver, but one of the ACKS is lost. Assume there are no timeouts and any out of order segments
received are thrown out.
TCP sender
TCP receiver
t= 1
1= 2
data segment
t= 3
data segment >
t= 4
data segment>
t= 5
data segment >
data segment P
t = 8
-t%= 9
t= 10
= 11
* ACK segment
ACK segment
ACK segment
t= 12
ACK segment
t = 15-
t= 16
t= 17
t = 18
Transcribed Image Text:Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. Suppose the initial value of the sequence number is 111 and every segment sent to the receiver each contains 194 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. And every segment needs to be acknowledged. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but one of the ACKS is lost. Assume there are no timeouts and any out of order segments received are thrown out. TCP sender TCP receiver t= 1 1= 2 data segment t= 3 data segment > t= 4 data segment> t= 5 data segment > data segment P t = 8 -t%= 9 t= 10 = 11 * ACK segment ACK segment ACK segment t= 12 ACK segment t = 15- t= 16 t= 17 t = 18
ACK
ACK segmen
t = 15
t = 16
t = 17
t = 18
1- What is the sequence number of the segment sent at t =1 ?
2- What is the sequence number of the segment sent at t=2?
3- What is the value of the ACK sent at t= 8 ?
4- What is the value of the ACK sent at t= 11?
nutes remaining
Transcribed Image Text:ACK ACK segmen t = 15 t = 16 t = 17 t = 18 1- What is the sequence number of the segment sent at t =1 ? 2- What is the sequence number of the segment sent at t=2? 3- What is the value of the ACK sent at t= 8 ? 4- What is the value of the ACK sent at t= 11? nutes remaining
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