Consider the figure below. M 2 2 P(x1, Y1) We can show that d(PM) + d(MQ) = d(PQ). %3D X1+ X2 X1 Y1+ Y2 Y1 X1 + X2 d(PM) + d(MQ) %3D - 2 Y2 Y1 X. X2-X1 V 1 (Y2-Y1 1 + (Y2 Y1 %3D X1 Y1) d(PQ) Use this result to explain why point M is the midpoint of segment PQ. +. Point M is the midpoint of segment PQ because ^1" ^2 = Y1+Y2. 2 Point M is the midpoint of segment PQ because (x2 - X1) = (2- Y1). Point M is the midpoint of segment PQ because d(PM) d(MQ). Point M is the midpoint of segment PQ because x, = Y, and x2=Y2-
Consider the figure below. M 2 2 P(x1, Y1) We can show that d(PM) + d(MQ) = d(PQ). %3D X1+ X2 X1 Y1+ Y2 Y1 X1 + X2 d(PM) + d(MQ) %3D - 2 Y2 Y1 X. X2-X1 V 1 (Y2-Y1 1 + (Y2 Y1 %3D X1 Y1) d(PQ) Use this result to explain why point M is the midpoint of segment PQ. +. Point M is the midpoint of segment PQ because ^1" ^2 = Y1+Y2. 2 Point M is the midpoint of segment PQ because (x2 - X1) = (2- Y1). Point M is the midpoint of segment PQ because d(PM) d(MQ). Point M is the midpoint of segment PQ because x, = Y, and x2=Y2-
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter87: An Introduction To G- And M-codes For Cnc Programming
Section: Chapter Questions
Problem 27A: Write a CNC G-code program to machine the part in the following figure, so that the tip of the tool...
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