Consider the figure below. M 2 2 P(x1, Y1) We can show that d(PM) + d(MQ) = d(PQ). %3D X1+ X2 X1 Y1+ Y2 Y1 X1 + X2 d(PM) + d(MQ) %3D - 2 Y2 Y1 X. X2-X1 V 1 (Y2-Y1 1 + (Y2 Y1 %3D X1 Y1) d(PQ) Use this result to explain why point M is the midpoint of segment PQ. +. Point M is the midpoint of segment PQ because ^1" ^2 = Y1+Y2. 2 Point M is the midpoint of segment PQ because (x2 - X1) = (2- Y1). Point M is the midpoint of segment PQ because d(PM) d(MQ). Point M is the midpoint of segment PQ because x, = Y, and x2=Y2-

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter87: An Introduction To G- And M-codes For Cnc Programming
Section: Chapter Questions
Problem 27A: Write a CNC G-code program to machine the part in the following figure, so that the tip of the tool...
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Question
E Hmwk - The..
M
M Mathway | Algebr..
G the expression f..
2/7/2022 A
Consider the figure below.
Q(x, y)
12
2.
P(x1, yı)
We can show that d(PM) + d(MQ) = d(PQ).
x,)° + (Y1 + y2
Y1)
X1+ X2
d(PM) + d(MQ) =
X1 + X2
X2
1.
+.
2.
2.
X2- X1
Y2- Y1
X2
2.
Y2 - Y1
+.
2.
2.
(x2 -*)* + (v2 - v1
2.
1.
Y2- Y1)
2.
X1)
- X1)
Y1
2.
xz – X1) + (rz -Ys)°
d(PQ)
Use this result to explain why point M is the midpoint of segment PQ.
Point M is the midpoint of segment PQ because ^1' 12
Y1+ Y2
2.
Point M is the midpoint of segment PQ because (x, - X1) = (Y2 - Y1).
Point M is the midpoint of segment PQ because d(PM)
d(MQ).
Point M is the midpoint of segment PQ because x, = y, and x, = Y2
Transcribed Image Text:E Hmwk - The.. M M Mathway | Algebr.. G the expression f.. 2/7/2022 A Consider the figure below. Q(x, y) 12 2. P(x1, yı) We can show that d(PM) + d(MQ) = d(PQ). x,)° + (Y1 + y2 Y1) X1+ X2 d(PM) + d(MQ) = X1 + X2 X2 1. +. 2. 2. X2- X1 Y2- Y1 X2 2. Y2 - Y1 +. 2. 2. (x2 -*)* + (v2 - v1 2. 1. Y2- Y1) 2. X1) - X1) Y1 2. xz – X1) + (rz -Ys)° d(PQ) Use this result to explain why point M is the midpoint of segment PQ. Point M is the midpoint of segment PQ because ^1' 12 Y1+ Y2 2. Point M is the midpoint of segment PQ because (x, - X1) = (Y2 - Y1). Point M is the midpoint of segment PQ because d(PM) d(MQ). Point M is the midpoint of segment PQ because x, = y, and x, = Y2
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