Consider the fmction f(x,y) = 6y2 + 4x2 – 12xy- 4y. Then: O (-1,-2/3) is a critical point and f has a local minimum at (-1,-2/3) O (-1,-2/3) is a critical point and f has a saddle point at (-1,-2/3) O None of these (1,1) is a critical point and f has a local maximum at (1,1)

Consider the fmction f(x,y) = 6y2 + 4x2 – 12xy- 4y. Then: O (-1,-2/3) is a critical point and f has a local minimum at (-1,-2/3) O (-1,-2/3) is a critical point and f has a saddle point at (-1,-2/3) O None of these (1,1) is a critical point and f has a local maximum at (1,1)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

Consider the fnction f(x, y) = 6y² + 4x² – 12xy – 4y. Then:
O (1,-2/3) is a critical point and f has a local minimum at (-1,-2/3)
O (1,-2/3) is a critical point and f has a saddle point at (1,2/3)
O None of these
O (1,1) is a critical point and f has a local maximum at (1,1)

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