Consider the following 3 permutations in S10: 0 = 1 2 3 4 5 6 7 8 1 4 5 6 8 10 7 9 2 9 10 3 fl= T= 1 2 2 5 10 4 9 3 4 5 6 7 7 6 1 2 3 4 5 6 7 8 9 10 10 9 8 4 3 2 1 5 6 7 8 3 9 10 8 1 (8.1) Compute 7μ-¹o. (8.2) Express as a product of disjoint cycles and then as a product of transpositions. (8.3) Find the smallest value of n so that " = i, where i is the identity permutation.
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- How to solve this with cohens d using Microsoft Excel Use alpha of 0.05 2 tail. Free Association (in seconds) Partially Controlled (in seconds)5.84 4.844.64 5.643.56 8.565.00 7.002.35 4.353.67 4.677.87 6.677.74 5.444.48 5.586.56 6.26Obtain the Z transform of 10/[s(s²+s+2)]A manufacturing company employs two inspecting devices to sample a fraction of their output for quality control purposes. The first inspection monitor is able to accurately detect 99.3% of the defective items it receives, whereas the second is able to do so in 99.7% of the cases. Assume that four defective items are produced and sent out for inspection. Let X and Y denote the number of items that will be identified as defective by inspecting devices 1 and 2, respectively. Determine the following. 1) fxy(x,y) 2) fx (x)3) fY|2 4) E(x)Show all work
- A manufacturing company employs two inspecting devices to sample a fraction of their output for quality control purposes. The first inspection monitor is able to accurately detect 99.3% of the defective items it receives, whereas the second is able to do so in 99.7% of the cases. Assume that four defective items are produced and sent out for inspection. Let X and Y denote the number of items that will be identified as defective by inspecting devices 1 and 2, respectively. Determine the following. 1) fxy(x,y) 2) fx (x)3) E(x)4) E(Y|X=2)5) V(Y|X=2)6) Are X and Y independent? Why?4.3.2 Let Y ∼ Uniform[0, 1], and let Xn = Yn. Prove that Xn → 0 with probability 1.How to solve this using Microsoft Excel Use alpha of 0.05 2 tail. Free Association (in seconds) Partially Controlled (in seconds)5.84 4.844.64 5.643.56 8.565.00 7.002.35 4.353.67 4.677.87 6.677.74 5.444.48 5.586.56 6.26
- 2) Find the expression for F(z) while solving the recurrence relation 2yk+2 − 3yk+1 + 7yk = kakbyusing Z-transform with the initial conditions y0 = a, y1 = bn alpha=0.05 alpha=0.014 0.950 0.9905 0.878 0.9596 0.811 0.9177 0.754 0.8758 0.707 0.8349 0.666 0.79810 0.632 0.76511 0.602 0.73512 0.576 0.70813 0.553 0.68414 0.532 0.66115 0.514 0.64116 0.497 0.62317 0.482 0.60618 0.468 0.59019 0.456 0.57520 0.444 0.56121 0.433 0.54922 0.423 0.53723 0.413 0.52624 0.404 0.51525 0.396 0.50526 0.388 0.49627 0.381 0.48728 0.374 0.47929 0.367 0.47130 0.361 0.46335 0.334 0.43040 0.312 0.40345 0.294 0.38050 0.279 0.36155 0.266 0.34560 0.254 0.33065 0.244 0.31770 0.235 0.30675 0.227 0.29680 0.220 0.28685 0.213 0.27890 0.207 0.27095 0.202 0.263100 0.197 0.256Does law of inverses hold for the following: 1. Addition table for Z9 2. Multiplication table for Z9 3. The following table: x 1 2 4 5 7 8 1 1 2 4 5 7 8 2 2 4 8 1 5 7 4 4 8 7 2 1 5 5 5 1 2 7 8 4 7 7 5 1 8 4 2 8 8 7 5 4 2 1
- A manufacturing company employs two inspecting devices to sample a fraction of their output for quality control purposes. The first inspection monitor is able to accurately detect 99.3% of the defective items it receives, whereas the second is able to do so in 99.7% of the cases. Assume that four defective items are produced and sent out for inspection. Let X and Y denote the number of items that will be identified as defective by inspecting devices 1 and 2, respectively. Determine the following. 1) E(x)2) E(Y|X=2)3) V(Y|X=2)4) Are X and Y independent? Why?Human blood types are classified by three gene forms A, B, and O. Blood types AA, BB, and OO are homozygous, and blood types AB, AO, and BO are heterozygous. If p, q, and r represent the proportions of the three gene forms to the popula-tion, respectively, then the Hardy-Weinberg Law asserts that the proportion Q of heterozygous persons in any specific population is modeled by Q(p, q, r) = 2(pq + pr + qr), subject to p + q + r = 1. Find the maximum value of Q.Suppose a researcher compares the means of two independent groups that have the same number of participants in each group. The researcher uses the .05 level of significance and obtains a calculated value of t of 2.11. At least how many participants must be in each group in order to reject the null hypothesis?A. 10B. 9C. 8D. 11