Consider the following message M=1010001101. The cyclic redundancy check (CRC) for this message using the divisor polynomial x5 + x4 + x² + 1 is?
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Consider the following message M=1010001101. The cyclic redundancy check (CRC) for this message using the divisor polynomial x5 + x4 + x² + 1 is?
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- consider the following message M = 1010001101. Calculate the cyclic redundancy check (CRC) for this message using the divisor polynomial 11011. Recompute the CRC at receiver side to verify your answer.Given that K=3 and the transmitted message is repeated 7 times, what is the value of R?Assume we have a code composed of 5 ternary codewords of varying lengths (1, 1, 2, 2, 3). How many unique messages comprised of two message symbols result in a series of four code symbols after encoding?
- What is the number of padding bits if the length of the original message is 2590 bits? Do we need padding if the length of the original message is already a multiple of 1024 bits?Question 1 What is the original message encrypted using the RSA system with n = 59 ·53 and e = 21 if theencrypted message is 0600 0190 0117? You must first find the inverse of 21 modulo 58 ·52. Full explain this question and text typing work only thanksShow all the steps to find value of CRC for dataword 10110101 and the divisor (polynomial value) is 10011. What is the value of CRC? What is binary value of Codeword that will be sent on the network Show all the steps to determine if there is any error in the received code word: 101101010100 where the divisor is 10011
- The following message uses a direct mapping of letters to numbers (i.e. A-1, B=2, c-3, etc.).Using the values D=17 and m=21, decrypt the following message:10 15 12 18 1 3 17 14 7 18 14 17 17 9 18 14Suppose Alice and Bob are going to communicate using AES in CBC mode. Unfortunately Alice's message length (in bytes) is not a multiple of 16. Suppose the last block of her message is just a single zero byte. How can she pad out the last block so that she can use CBC mode? Since this needs to be a reversible operation, how does Bob recognize the padding and remove it?The very last block of a message encrypted with AES-256 in CBC mode is 15 bytes long and ends with the bytes: 0102030405060708090a0b0c0d0e0f When padded in accordance with PKCS #7 with 16-byte blocks, what is the complete value of the last block? *Please explain how you have solved this, thank you!!
- A sender sends 01110001; the receiver receives 01000001.if simple parity is used, can the receiver detect the error? Explain your answer.9. Given h = Sha256(K || M), where K is a secret and "||" means concatenation (no padding is involved in calculating h). Please describe how one can calculate Sha256(K || X) for a different message X without knowing K.Compute CBC-MAC for a message of 16 bits, “ABCD” (in Hexa). Assume a block size of 8 bits with an IV=C9 (in hexa). For simplicity, assume the encryption to be a simple XOR of the key with the plaintext. Let the encryption key be D8 (in Hexa). (Hint: Divide the message into blocks of 8 bits each; XOR each block with the previous cipher output; then encrypt this with the key. For the first block, XOR it with IV.