Consider the following reaction CH3CH2CO,CH2CH3 (g) H20 (g) CH;CH,CO>H (g) CH;CH2OH (g) Kp = 0.236 at 398 K a) A reaction mixture initially contains a CH3CH2CO2CH2CH3 with a partial pressure of 1255 mbar and a H2O with partial pressure of 1255 mbar at 398 K. Calculate the equilibrium partial pressure of each of the products and reactants. Hint: The x is small assumption is not valid here because K is close to unity. There is another way to avoid the quadratic equation. b) What is Ke at 398 K?
Consider the following reaction CH3CH2CO,CH2CH3 (g) H20 (g) CH;CH,CO>H (g) CH;CH2OH (g) Kp = 0.236 at 398 K a) A reaction mixture initially contains a CH3CH2CO2CH2CH3 with a partial pressure of 1255 mbar and a H2O with partial pressure of 1255 mbar at 398 K. Calculate the equilibrium partial pressure of each of the products and reactants. Hint: The x is small assumption is not valid here because K is close to unity. There is another way to avoid the quadratic equation. b) What is Ke at 398 K?
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter17: Spontaneity, Entropy, And Free Energy
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CONSIDER THE FOLLOWING REACTION IN THE IMAGE BELOW
a) A reaction mixture initially contains a CHaCH2CO2CH2CH3 with a partial pressure of 1255 mbar and a H20 with
partial pressure of 1255 mbar at 398 K. Calculate the equilibrium partial pressure of each of the products and
reactants.
Hint: The x is small assumption is not valid here because K is close to unity. There is another way to avoid the
quadratic equation.
b) What is Ke at 398 K?
Transcribed Image Text:Consider the following reaction
CH3CH2CO,CH2CH3 (g) +
H20 (g)
CH;CH,CO,H (g) +
CH;CH,OH (g)
Kp = 0.236 at 398 K
a) A reaction mixture initially contains a CH3CH2CO2CH2CH3 with a partial pressure of 1255 mbar and a H20 with
partial pressure of 1255 mbar at 398 K. Calculate the equilibrium partial pressure of each of the products and
reactants.
Hint: The x is small assumption is not valid here because K is close to unity. There is another way to avoid the
quadratic equation.
b) What is Kc at 398 K?
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