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Consider the following system of linear equations. 5х +у-3z %3D- 54 — 3х — 2у = 29 2x -z = -19 Solve the system by completing the steps below to produce a reduced row-echelon form. R,, R,, and R, denote the first, second, and third rows, respectively.

Consider the following system of linear equations. 5х +у-3z %3D- 54 — 3х — 2у = 29 2x -z = -19 Solve the system by completing the steps below to produce a reduced row-echelon form. R,, R,, and R, denote the first, second, and third rows, respectively.

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Systems Of Equations And Inequalities
Section6.3: Multivariable Linear Systems
Problem 76E: The number of sides x and the combined number of sides and diagonals y for each of three regular...
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Consider the following system of linear equations. 5x +y - 3z = - 54 — 3х - 2у = 29 2x -z = -19 Solve the system by completing the steps below to produce a reduced row-echelon form. R,, R,, and R, denote the first, second, and third rows, respectively. The arrow notation stands for "replaces," where the expression on the left of the arrow replaces the expression on the right. 5 1 -3 -54 Here is the augmented matrix: -3 -2 29 2 -1 i -19 Enter the missing coefficients for the row operations. 54 1 (1) -3 -2 29 2 - 19 1 1 5 54 5 5 (3) ·R, +R, → Ry: 7 9. 17 (2) 5 I R, +R3 + R3: 2 13 5 54 1 5 5 9 17 O R, → R,: 1 (3) 7 13 5 olo 1_5 ㅇ
Transcribed Image Text:Consider the following system of linear equations. 5x +y - 3z = - 54 — 3х - 2у = 29 2x -z = -19 Solve the system by completing the steps below to produce a reduced row-echelon form. R,, R,, and R, denote the first, second, and third rows, respectively. The arrow notation stands for "replaces," where the expression on the left of the arrow replaces the expression on the right. 5 1 -3 -54 Here is the augmented matrix: -3 -2 29 2 -1 i -19 Enter the missing coefficients for the row operations. 54 1 (1) -3 -2 29 2 - 19 1 1 5 54 5 5 (3) ·R, +R, → Ry: 7 9. 17 (2) 5 I R, +R3 + R3: 2 13 5 54 1 5 5 9 17 O R, → R,: 1 (3) 7 13 5 olo 1_5 ㅇ
1 1 5 3 54 5 17 O R, - R: 1 (3) 7 7 2 1 13 5 6 ! 79 1 0 7 (+) *-* 7 ·R, +Rq → R;: 9 0 1 7 17 (4) 7 O R2 +R3 → R3: 5 25 0 0 7 7 79 1 0 7 7 (5) O R3 - R3: 17 0 1 7 0 0 1 5 Enter the missing coefficient for the row operation, fill in the missing matrix entries, and give the solution. (*) ** ·R3+Rq → R¡: 1 (6) 0 1 I R3 + R2 → R2: 0 0 1 :- 0 y - 0 : - 0 Solution:
Transcribed Image Text:1 1 5 3 54 5 17 O R, - R: 1 (3) 7 7 2 1 13 5 6 ! 79 1 0 7 (+) *-* 7 ·R, +Rq → R;: 9 0 1 7 17 (4) 7 O R2 +R3 → R3: 5 25 0 0 7 7 79 1 0 7 7 (5) O R3 - R3: 17 0 1 7 0 0 1 5 Enter the missing coefficient for the row operation, fill in the missing matrix entries, and give the solution. (*) ** ·R3+Rq → R¡: 1 (6) 0 1 I R3 + R2 → R2: 0 0 1 :- 0 y - 0 : - 0 Solution:
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