Consider the following system: x+y+2z = b, x+ 2y + 3z = b2, 2x +y+3z bz. %3D The system has infinitely many solutions if: A) b – 362 + bz =0 B) bị +b2 - 3b3 = 0 C) 3b - -チ0 D) 3b – b2 - by =0 %3D

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