Consider the full-wave rectifier circuit below. RL= 10 kS, V₁ = 0.7V, the input voltage V₁ = 120sin(2 60t) V(rms). The transformer turns ratio ₁ = 20, where N₁ is the number of N₂ turns in the primary and N₂ is the number of turns in each of the secondary winding. a) Plot Vs and Vo on the same graph for two periods, assuming there is no capacitor (C = 0). b) Determine the capacitor value so that the ripple voltage is limited to 1V. Plot the output voltage on the graph from part a) c) Indicate on the graph where diode D₂ has the maximum reverse bias and determine Peak Inverse Voltage (PIV). D1

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Consider the full-wave rectifier circuit below. RL = 10 kQ, Vy= 0.7V, the input voltage
N₁
V₁ = 120sin(2 60t) V(rms). The transformer turns ratio = 20, where N₁ is the number of
N₂
turns in the primary and N₂ is the number of turns in each of the secondary winding.
a) Plot Vs and Vo on the same graph for two periods, assuming there is no
capacitor (C = 0).
b) Determine the capacitor value so that the ripple voltage is limited to 1V. Plot
the output voltage on the graph from part a)
c)
Indicate on the graph where diode D₂ has the maximum reverse bias and
determine Peak Inverse Voltage (PIV).
VI
Vs
Vs
D1
KH
KH
D2
с
RL
VO
Transcribed Image Text:Consider the full-wave rectifier circuit below. RL = 10 kQ, Vy= 0.7V, the input voltage N₁ V₁ = 120sin(2 60t) V(rms). The transformer turns ratio = 20, where N₁ is the number of N₂ turns in the primary and N₂ is the number of turns in each of the secondary winding. a) Plot Vs and Vo on the same graph for two periods, assuming there is no capacitor (C = 0). b) Determine the capacitor value so that the ripple voltage is limited to 1V. Plot the output voltage on the graph from part a) c) Indicate on the graph where diode D₂ has the maximum reverse bias and determine Peak Inverse Voltage (PIV). VI Vs Vs D1 KH KH D2 с RL VO
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