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Consider the function f(x) = 3 - 3a2, -4 < x < 2.The absolute maximum value isPreviewand this occurs atPreviewThe absolute minimum value isPreviewand this occurs atPreviewGet help: Video

Question
Consider the function f(x) = 3 - 3a2, -4 < x < 2.
The absolute maximum value is
Preview
and this occurs at
Preview
The absolute minimum value is
Preview
and this occurs at
Preview
Get help: Video
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Consider the function f(x) = 3 - 3a2, -4 < x < 2. The absolute maximum value is Preview and this occurs at Preview The absolute minimum value is Preview and this occurs at Preview Get help: Video

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Step 1

Firstly, we find critical point of the given function, which is a  point at which f'(x)=0

Thus we find f'(x) and then solve the equation f'(x)=0 to find critical point

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Step 2

Now, we find the value of...

f(-4) 3-3(-4)= 3-48 = 45
f(0) 3-3(0)3
f(2) 3-3(2)3-12--9
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f(-4) 3-3(-4)= 3-48 = 45 f(0) 3-3(0)3 f(2) 3-3(2)3-12--9

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Tagged in

Math

Calculus

Derivative

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