Consider the function f(x) = 5x10 + 4x° – 2x* – 7. %3D Enter the antiderivative of f(x) + C

Q: Find dy/dx by implicit differentiation.   1) x3 + x4y4 + y7 = 5   2) x^2 / x+y = y2 + 7

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Q: Find the value df (a) that Make ECX) is Contincity at X- Ž

A: Given that :f(x)=cosx2x-π      ,             x≠012a2-3a+4      ,   x=0

Q: sec2 x dx sec2 x – 1 f.

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Q: 2x2 +4 Find the general antiderivative of f (x) =sin (x) + x²

A: Antiderivative is another name for integration of f. Therefore to find the anti derivative of f we…

Q: Use Version 1 of the Chain Rule to Calculate dy/dx

A: y=5x2+11x20Chain rule:dydx=dydu.dudx

Q: r3 V9-x² »6-x-y dz dy dx in the order dz dx dy 0,

A: Given triple integral is ∫03∫09-x2∫06-x-ydzdydx

Q: Differentiate the function. y = V 3x2 + 8x + 1 dy dx

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Q: Determine dy for y=VX2+1 . dx2 alx

A: Obtain the second derivative as follows.

Q: Find dy/dx for (x+y)3=x3+y3,at the point  (-1,1)

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Q: 4 dx. x'V16-x (c) By using x= 4sin (0), find

A: We have to find integration by substitution

Q: find the Dx [y] by implicit differentiate of x3+5y3=2

A: Given :           x3 + 5y3 = 2   To find Dx[y] :

Q: 1. S(3 – 2x – x*) dx

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Q: Find for the following functions: - dx 1- y = (Inx. Vsin x) 2- f(x) = xcos2x

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Q: Differentiate the function. y=(4x-4)° (3-x)? dy dx

A: Given query is to find the derivative of the expression.

Q: dx S COsxtanx

A: Here we will solve the given integration,

Q: 4. Use the contour integration to find f G dx. 1 x4+16

A: Answer: π/(16√2)

Q: Differentiate the function. y = (3x-4) (2-x*)° dy %3D dx

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Q: Q2: Find the integration by applying substitution method: 7 dX (X - 1)VX- 2x - 48

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Q: Integrate the function. 8 dx V36 - 64x2 X+ C sin-1 + C -1 + C D 4 tan-1 3. B

A: Given:       ∫836-64x2dx  substitute u=4x3→dudx=43                   dx=34du         =∫636-36u2du…

Q: Find of/dx and dfldy. f(x,y)% 3 (3xy-1) of

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Q: b. y = cosh(arctan 3x) C. y = 4a/ cosh a d²y d. for x = 4v2t2 + a, y = a² – t² dx2 %3| -

A: Given functions are  b) y=cosh(arctan3x) c) y=4acosha d) d2ydx2 for x=42t2+a , y=a2-t2

Q: x'dx √√x(1-x)

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Q: dx S (x+2)Vx+11

A: Given:  I=∫dx(x+2)x+11 Use the substitution method to evaluate the integration. substitute…

Q: Q4) Use the chain rule to express dy /dx in terms of x and y t2 y = t2+1 and t = 3x3 – 3 where x =1

A: Given y=t2t2+1 and t=3x3-3 and x=1

Q: Find an antiderivative for f(x) = lxl.

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Q: Solve using the integrating factors by inspection (y²-3-x) dy + ydx =0

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Q: dx 1-t+ x-tx dt

A: Given, dxdt=1-t+x-tx The equation is separable. Write it in differential form and integrate both…

Q: Solve the DE using Variation of Parameters: y"+y = sec' x %3D

A: Given  The differential equation using variation of parameters. y''+y=sec3x

Q: Find d2y/dx2 by implicit differentiation: a. x3 + y3 = 1 b. y2 = 1 -2/x.

A: a. Given,

Q: Solve using the integrating factor by inspection  (2x²y - y²x + yx) dx + (3x³ - 4x²y + 3x²) dy = 0…

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Q: Find the solution of the DE using reduction Order (D2 + 4)y = sinx

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Q: What is the I.F of dy/dx = y - xy^3e^(-2x)?

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Q: Q2: Find the integration by applying substitution method: 7 dX (X – 1)VX2 – 2x - 48

A: Given,             ∫7x-1x2-2x-48dx

Q: The approximation of I = f(x-3)** dx by composite Trapezoidal rule with n=4 is:

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Q: Find dy/dx by implicit differeniation x2y+y2x =- 2

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Q: Evaluate the implicit function by finding dy/dx of x³+3y=3xy

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Q: * J²Z d²z дуг dx²² 1 = tan ³x tany - tanxton³y

A: Given that  ∂2z∂x2-∂2z∂y2=tan3xtany-tanxtan3y

Q: Find the intergral of i. SVīdx ii. (x - 1)dx

A: According to Bartley guidelines I have, to solve only first question so repost the problem for…

Q: Find dy/dx for 3sin(x+y) - 2e^y =6x^3 by using implicit differentation

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Q: Find f. (Use C for the constant of the first antiderivative and D for the constant of the second…

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Q: Find oy for dx2

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Q: Q2 \ Evaluate .1 dx by using trapezoidal rule. 1+x2

A: See the details solution in below

Q: 1 B3. Evaluate dx, using substitution method.

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Q: Q4/ A/ Find the integration for the following functions (chose three) 1- sa (3x³+3x-5x²) dx 2 - S 2x…

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Q: Find dY for the function y= cos² 3X+ VSin x dx

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Q: Differentiate the function. y=[(sx +2x+3) (x-3)]² dy dx II

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Q: (x+6)dx (x+2)?

A: To evaluate: ∫x+6(x+2)2dx