Consider the function second xs = head (tail xs) What is its type? Explain why "second" has the type that it has, i.e., "tail :: [a] -> [a]", hence "xs :: [a]", and "head :: [a] -> a", etc. Why does chaining them together like in the definition of "second" give us the type that it has? Note: this will use the fact that if "f" is a function that maps arguments of type "a" to results of type "b", and "e" is an expression of type "a", then the application "f e" has type "b", that is: if "f :: a -> b" and "e :: a" then "f e :: b" 5. Consider the function swap (x,y) = (y,x) What is its type? Why can "x" and "y" correspond to different types in general?

Consider the function second xs = head (tail xs) What is its type? Explain why "second" has the type that it has, i.e., "tail :: [a] -> [a]", hence "xs :: [a]", and "head :: [a] -> a", etc. Why does chaining them together like in the definition of "second" give us the type that it has? Note: this will use the fact that if "f" is a function that maps arguments of type "a" to results of type "b", and "e" is an expression of type "a", then the application "f e" has type "b", that is: if "f :: a -> b" and "e :: a" then "f e :: b" 5. Consider the function swap (x,y) = (y,x) What is its type? Why can "x" and "y" correspond to different types in general?

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter13: Overloading And Templates

Section: Chapter Questions

Problem 36SA

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