Consider the graph below. Find the equation for the line tangent to the graph at the point (2,-2). Write your answer in slope-intercept form.  (y+4)^2=4(x-1)

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A: Implicit differentiation is ordinary differentiation but the function y is not given as an explicit…

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Q: Find a parabola with equation y = ax² + bx + c that has slope 4 at x = 1, slope -16 at x = -1, and…

A: We know slope of a curve y=f(x) is given by, dydx=f'(x)

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A: Given equation of parabola is y=-2x2+12x-5. To find the vertex using derivative. Solution: We know…

Q: The slope of the curve defined by the equation y-x + x =-2 at the point (-1,0) is %D

A: Derivatives can be defined as rate of change of function with respect to an independent variable. It…

Q: Find the equation of the line tangent to the curve (x-2)^2=-4(y+3) at (2,-3)

A: Given data:     The expression for the equation of the curve is: (x-2)2=-4(y+3). The given point is:…

Q: Determine an equation of the line tangent to the graph at the point (3,8)

A: We find f'(x) using the quotient rule. And plug x=3 in it to find f'(3)

Q: The line y = -4x + 16 is tangent to the graph of 100 y : x + 6 at the point help (points)

A: Given the equation of a tangent line:

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A: The initial height of the balloon is 131 meters. The balloon begins to ascend at a rate of 14 meters…

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A: Given that y'=-y5xdydx=-y5x

Q: Find the equation of the tangent line to the graph of f(x)=-3x2-5 at the point (2,-17). Write your…

A: Given function    f(x) = -3x2-5Differentiating ,  f'(x) = ddx(-3x2-5)…

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A: In this question, we will compute the equation of the tangent line of the given curve.

Q: What is the equation of the line tangent to the graph of y = x(1-2x)^3 at the point (-1,1)?

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Q: 10. Find the slope-intercept form of the equation of the line tangent to the graph of y arctan(9x)…

A: Given y = arc tan9xand x=39here we find the slope - intercept form of the equation of the line…

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A: To find: the equation of the family of curves whose slope at any point (x,y) is 3x2+4  We know that…

Q: Help to find the equation of the line tangent to the curve y = 6 / x when x = 3.

A: Given curve is y=6x When x=3 then y=63=2 So, point is (3,2) Equation of tangent line at any point…

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Q: Write the equation of the tangent line to the graph of  y = (8x2 − 6x + 2)(1 + 2x) at x = 1. Check…

A: the equation of the tangent line to the graph of, y=(8x2−6x+2)(1+2x) at x=1   y=(812−61+2)(1+21)…

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Q: Find the x-and y-intercepts of the line that is tangent to the curve y = x3 at the point (-2, -8).

A: The equation of tangent line to a curve y = f(x) at a point (a,b) is given by the below equation.

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Q: Determine the equation of the line tangent to the graph of f ( x ) = 3 x 2 − x + 4 at x = − 1.  Give…

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Q: ) Listen > Find the slope of the tangent line to the graph of 6x2 + y² = 25 at(-2,-1).

A: given,      6x2+y2=25  at  -2,-1

Q: Find the slope of the curve at the given point: 1. ( X+2y)^2 =x+10 at (-1, 2)

A: Here I am attaching image so that you understand each and every step. slope of the curve given at…

Q: What is the slope-intercept form of the equation of the tangent line to y=x²+2x at x=0?

A: At x = 0, y = 0+0 =0  So, the tangent line passes through (0,0) .

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Q: Find an equation of the curve that passes through the point (1, 1), and has the given slope y′ = −…

A: y'=-9x16yPasses through (1,1)Formula∫xndx=xn+1n+1+C

Q: 11. What is the slope of the tangent line to the curve y = 3x2 - 5 at point (-1,-2)? а. -5 b. -6…

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Q: 2x at x =1 y = Зх-1

A: Find dydx as follows. y=2x23x-1dydx=22x3x-1-3x23x-12dydx=23x2-2x3x-12 Find dydx at x=1 as follows.…

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A: *given:- slope, dy/dx = -4x points (x, y) = (1, 13)   *to find:- equation of the curve.

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Q: Find the equation of the line tangent to the graph of y = 4x'-9x-7 at the point (1,8).

A: Method to find tangent at a point of any curve.

Q: 14. Find the slope of the curve y = 2x3 – 3x at (-1 , 1)

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Q: What is the slope of the curve y = 1 + x^2 at the point y = 10?

A: We will solve the following

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A: We have to find the equation of tangent line.

Q: Find the slope of the curve y² = 3x + 1 at the point (- ,0). Draw the graph of the curve.

A: y2=3x+1 Differentiating with respect to x, we get 2y·dydx=31+0⇒2y·dydx=3⇒dydx=32y Now slope of the…

Q: Find the equation of the line that is tangent to the graph of y= x^3 +4/x^2 at point (2,9)

A: The equation of tangent line to y=f(x) at (x0,y0) is y-y0=f'(x0)(x-x0)