Question

In Intermediate Algebra for College, 7th Edition, Chapter 4, problem 29E: when simplifying "6 - 2x + 4" how do you get "14 - 2x"? Shouldn't it simplify to "-2x + 10"?

Consider the inequality:
6 - 3(3z 12(0z 50)
Now, expand the inequality:
6-(을-3x-2-12) (10x + 50)
(2x-8) < (음 . 10 50)
6 (2 8) < (4c 20)
Now, further simplify both sides:
6 - 2x +4 420
14 - 2x 4 20
Now, subtract 4x from both sides:
14 6x 20
Now, subtract 14 from both sides:
Now, divide both sides by-6:
6
r 2-1
Expand
Transcribed Image Text

Consider the inequality: 6 - 3(3z 12(0z 50) Now, expand the inequality: 6-(을-3x-2-12) (10x + 50) (2x-8) < (음 . 10 50) 6 (2 8) < (4c 20) Now, further simplify both sides: 6 - 2x +4 420 14 - 2x 4 20 Now, subtract 4x from both sides: 14 6x 20 Now, subtract 14 from both sides: Now, divide both sides by-6: 6 r 2-1

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