2. Consider the Karnaugh map of a Boolean function k(w, x, y, z) shown atright.I(a) Use the Karnaugh map to find the DNF for k(w, x, y, z).(b) Use the Karnaugh map algorithm to find the minimal expression fork(w, x, y, z).x y z h(x, y, z)001111OOOO:0000нноонно101 1LOLOLOL3. Use a don't care Karnaugh map to find a minimal representation for a Boolean expression h(x,y,z) agreeingwith the incomplete I/O table below:10001OLO00NEINxyyz 1INWXyz 1ÿz1wx wx woxxy xy fy1111

A Karnaugh map is a visual tool used to simplify Boolean expressions. It is a two-dimensional grid…

- Consider the Karnaugh map of a Boolean function k(w, x, y, z) shown at right. I (a) Use the Karnaugh map to find the DNF for k(w, x, y, z). (b) Use the Karnaugh map algorithm to find the minimal expression for k(w, x, y, z). yz 1 yz yz 1 ýz 1 1 1 1 1

- Consider the Karnaugh map of a Boolean function k(w, x, y, z) shown at right. I (a) Use the Karnaugh map to find the DNF for k(w, x, y, z). (b) Use the Karnaugh map algorithm to find the minimal expression for k(w, x, y, z). yz 1 yz yz 1 ýz 1 1 1 1 1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Problems on Growing Functions

For a given set of functions f and g, the growth of functions states that the function g grows as fast as the function f. The growth rate of algorithms helps determine the algorithm's efficiency and compare its performance to other algorithms.

Question

2. Consider the Karnaugh map of a Boolean function k(w, x, y, z) shown at
right.
I
(a) Use the Karnaugh map to find the DNF for k(w, x, y, z).
(b) Use the Karnaugh map algorithm to find the minimal expression for
k(w, x, y, z).
x y z h(x, y, z)
0
0
1111OOOO:
0
0
0
0
нноонно
10
1 1
LOLOLOL
3. Use a don't care Karnaugh map to find a minimal representation for a Boolean expression h(x,y,z) agreeing
with the incomplete I/O table below:
1
0
0
0
1
OLO
0
0
NE
IN
xy
yz 1
IN
WX
yz 1
ÿz
1
wx wx wox
xy xy fy
1
1
1
1

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