Consider the reaction below between diborane, B2H6 , and oxygen to produce boric acid, HBO2, and water, H20. How many gram of B2H6 is needed to produce 36.15 gram of boric acid if the percentage yield of reaction is 86.23%. Consider amount of O2 is excess. B2H6 + 302 → 2HBO2 + 2H20 Molecular mass (g/mol) HBO2: 43.82 B2H6 : 27.66 O2: 32.00 H2O: 18.02 52.92 g O 13.23 g 26.46 g 11.41 g 22.82 g

Chemistry: Principles and Reactions
8th Edition
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Author:William L. Masterton, Cecile N. Hurley
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Chapter3: Mass Relations In Chemistry; Stoichiometry
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Consider the reaction below between diborane, B2H6 , and oxygen to produce boric acid,
HBO2, and water, H20. How many gram of B2H6 is needed to produce 36.15 gram of
boric acid if the percentage yield of reaction is 86.23%. Consider amount of O2 is excess.
B2H6 + 302 –→ 2HBO2 + 2H20
Molecular mass (g/mol)
НВО2: 43.82
B2H6: 27.66
О2: 32.00
H2O: 18.02
O 52.92 g
O 13.23 g
26.46 g
O 11.41 g
O 22.82 g
Transcribed Image Text:Consider the reaction below between diborane, B2H6 , and oxygen to produce boric acid, HBO2, and water, H20. How many gram of B2H6 is needed to produce 36.15 gram of boric acid if the percentage yield of reaction is 86.23%. Consider amount of O2 is excess. B2H6 + 302 –→ 2HBO2 + 2H20 Molecular mass (g/mol) НВО2: 43.82 B2H6: 27.66 О2: 32.00 H2O: 18.02 O 52.92 g O 13.23 g 26.46 g O 11.41 g O 22.82 g
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