Consider the reaction of a 20.0 mL of 0.220 M C̟H̟NHCI (Ka = 5.9 x 10*) with 12.0 mL of 0.241 M CSOH. With 0.00151 moles of C_H¸NH and 0.00289 moles of CHN in the beaker, what would be the pH of this solution after the reaction goes to completion and the system reaches equilibrium? 5

Chemistry: Principles and Reactions
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Chapter14: Equilibria In Acid-base Solutions
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Problem 75QAP: A diprotic acid, H2B(MM=126g/moL), is determined to be a hydrate, H2B xH2O. A 10.00-g sample of this...
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Question 13.g of 14
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Consider the reaction of a 20.0 mL of 0.220 M C̟H̟NHCI
(Ka = 5.9 x 10*) with 12.0 mL of 0.241 M CSOH.
%3D
With 0.00151 moles of C H¸NH* and 0.00289 moles of
CHN in the beaker, what would be the pH of this solution
after the reaction goes to completion and the system
reaches equilibrium?
5 "5
1
2
3
4
C
7
8
9.
+/-
х 100
+
Transcribed Image Text:Question 13.g of 14 Submit Consider the reaction of a 20.0 mL of 0.220 M C̟H̟NHCI (Ka = 5.9 x 10*) with 12.0 mL of 0.241 M CSOH. %3D With 0.00151 moles of C H¸NH* and 0.00289 moles of CHN in the beaker, what would be the pH of this solution after the reaction goes to completion and the system reaches equilibrium? 5 "5 1 2 3 4 C 7 8 9. +/- х 100 +
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