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Consider the regular subdivision of the interval [a, b] as a - x0 < x1 < x2 < x3 < 14 = b, with the step size h = x -X, and define the function f on [a, b) such that f(a) - f(b) - 1.f(x1) = 1.5, f(x2) = f(x3) - 2. Suppose that the length of the interval fa, b] is 3, then the approximation of I= (x)dx using composite Simpson's rule with n 4 is: %3D O 5 10/3 5/2 5/3

Consider the regular subdivision of the interval [a, b] as a - x0 < x1 < x2 < x3 < 14 = b, with the step size h = x -X, and define the function f on [a, b) such that f(a) - f(b) - 1.f(x1) = 1.5, f(x2) = f(x3) - 2. Suppose that the length of the interval fa, b] is 3, then the approximation of I= (x)dx using composite Simpson's rule with n 4 is: %3D O 5 10/3 5/2 5/3

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.2: Exponential Functions
Problem 58E
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Consider the regular subdivision of the interval [a, b] as a = x0 < x1 < x2 < x3 < x4 = b, with the step size h = x41- X, and define the function f on [a, b] such that f(a) = f(b) = 1, f(x1) = 1.5, f(x2) = f(x3) = 2. Suppose that the length of the interval [a, b] is 3, then the approximation of I= f(x)dx using composite Simpson's rule with n= 4 is: 10/3 5/2 5/3 O O O O
Transcribed Image Text:Consider the regular subdivision of the interval [a, b] as a = x0 < x1 < x2 < x3 < x4 = b, with the step size h = x41- X, and define the function f on [a, b] such that f(a) = f(b) = 1, f(x1) = 1.5, f(x2) = f(x3) = 2. Suppose that the length of the interval [a, b] is 3, then the approximation of I= f(x)dx using composite Simpson's rule with n= 4 is: 10/3 5/2 5/3 O O O O
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