Please help me with this question. Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside thewater. Since the indices of refraction of air and water are different, the light rays coming from the diverand the instructor are refracted at the surface, changing their apparent position with respect to each other.The diver sees the instructor at an apparent angle of 0 = 35°, measured from the normal to the interface.Known Variables0₂=35°945Find the height of the instructor's head above the water in meters, noting that you will first have to= 1.33calculate the angle of incidence (you can take the indices of refraction to be n = 1 for air and nfor water).h =Find the apparent depth of the diver's head below water as seen by the instructor in meters, assuming thediver and his image both have the same horizontal distance along the surface of the water.x=

Given:apparent angle, θa = 35oFrom the figure below,OF = a = 2.0 mOE = b = 2.0 mAsked:1) real height…

Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside the water. Since the indices of refraction of air and water are different, the light rays coming from the diver and the instructor are refracted at the surface, changing their apparent position with respect to each other. The diver sees the instructor at an apparent angle of 0₂ = 35°, measured from the normal to the interface.

Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside the water. Since the indices of refraction of air and water are different, the light rays coming from the diver and the instructor are refracted at the surface, changing their apparent position with respect to each other. The diver sees the instructor at an apparent angle of 0₂ = 35°, measured from the normal to the interface.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter38: Refraction And Images Formed By Refraction

Section: Chapter Questions

Problem 104PQ

See similar textbooks

Similar questions

A physicist directs a laser beam through a transparent medium, toward one surface of an equilateral prism. (The beam travels, and remains in, the plane of the page.) Incident on Surface 1 at an angle ?1, the beam then encounters Surface 2 from within the prism. If the angle of incidence at Surface 2 equals ?c , the critical angle for this prism, what is the original incidence angle, ?1 (in degrees)? The critical angle in this case is ?c = 40.5°. 40.5° 40.5° A prism in the shape of an equilateral triangle is shown. The triangle is upside down such that the base of the triangle is at the top of the figure and the apex is at the bottom. A laser beam comes in from the top left, moves down and to the right and is incident on the center of the base of the triangle. This surface is labeled Surface 1. The incident beam makes an angle of ?1 with the vertical. Within the prism, the beam continues to move down and to the right but at a slope which is steeper than the initial beam. It is incident…
The left end of a long glass rod 8.00 cm in diameter, with an index of refraction of 1.60, is ground and polished to a convex hemispherical surface with a radius of 4.00 cm. An object in the form of an arrow 1.50 mm tall, at right angles to the axis of the rod, is located on the axis 24.0 cm to the left of the vertex of the convex surface. Find the position and height of the image of the arrow formed by paraxial rays incident on the convex surface. Is the image erect or inverted?
A man inside a spherical diving bell watches a fish through a window in the bell, as in the figure below. If the diving bell has radius R = 1.88 m and the fish is a distance p = 1.32 m from the window, calculate the image distance and the magnification. Neglect the thickness of the window. (Use 1.333 and 1.000 for the indices of refraction of water and air, respectively.) An illustration shows a person inside a submerged spherical diving bell of radius R. The person observes a fish shown to be a distance p beyond the diving bell's viewing window. (a) the image distance (in m) answer in m (b) the magnification
The drawing shows a top view of a square room. One wall is missing, and the wall on the right is a mirror. From point P in the center of the open side, a laser is pointed at the mirrored wall. At what angle of incidence must the light strike the right-hand wall so that, after being reflected, the light hits the left corner of the back wall?
A bear is sitting on a rock in the middle of a calm river when he observes a fish directly below. If the apparent depth of the fish is 1.1 m, what is the actual depth at which the fish is swimming? The index of refraction of water is 1.33.
A beam of light enters a flint glass semicircular disk with an index of refraction of ng = 1.66 at the midpoint of the flat side as shown in the figure. Determine the angle of incidence in air such that the refracted light will travel through the glass along a normal to the semicircular surface and hit a projection screen with the coordinates x = 5.50 cm and y = 18.1 cm. =___°
A person looking into an empty container is able to see the far edge of the container’s bottom as shown. The height of the container is h, and its width is d. When the container is completely filled with a fluid of index of refraction n and viewed from the same angle, the person can see the center of a coin at the middle of the container’s bottom as shown. (a) Show that the ratio h/d is given by h/d = √n2 -1/4 - n2(b) Assuming the container has a width of 8.00 cm and is filled with water, use the expression above to find the height of the container. (c) For what range of values of n will the center of the coin not be visible for any values of h and d?
For a particular transparent medium surrounded by air, find the polarizing angle θp in terms of the critical angle for total internal reflection θc.
• Light is refracted as it travels from a point A in medium 1 to apoint B in medium 2. If the index of refraction is 1.33 in medium1 and 1.51 in medium 2, how much time does it take for light to gofrom A to B, assuming it travels 331 cm in medium 1 and 151 cm inmedium 2?
An aquarium contains a 5-cm layer of water (n = 1.33) floating on top of carbon disulfide (n = 1.628). If the angle of incidence into the water from the air is 30°, what is the angle of refraction into the carbon disulfide?
A ray of light strikes a flat glass block at an incidence angle of ?1 = 34.4°. The glass is 2.00 cm thick and has an index of refraction that equals ng = 1.20. A light ray incident on a glass block of thickness 2.00 cm is shown. The ray travels down and to the right and is incident to the top of the block at an angle ?1 to the normal of the surface. The ray inside the block moves down and to the right but at a steeper slope than the incident ray, making an angle of ?2 with the vertical. It is incident on the bottom surface of the block, making an angle of ?3 with the vertical, and exits moving down and to the right, at a less steep slope, making an angle of ?4 with the vertical. A dashed line extends from the original path of the ray down in the block and is shown to be a distance d from the ray that exits the glass block. (a) What is the angle of refraction, ?2, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2…
A ray of light strikes a flat glass block at an incidence angle of ?1 = 34.4°. The glass is 2.00 cm thick and has an index of refraction that equals ng = 1.20. A light ray incident on a glass block of thickness 2.00 cm is shown. The ray travels down and to the right and is incident to the top of the block at an angle ?1 to the normal of the surface. The ray inside the block moves down and to the right but at a steeper slope than the incident ray, making an angle of ?2 with the vertical. It is incident on the bottom surface of the block, making an angle of ?3 with the vertical, and exits moving down and to the right, at a less steep slope, making an angle of ?4 with the vertical. A dashed line extends from the original path of the ray down in the block and is shown to be a distance d from the ray that exits the glass block. d) The distance d separates the twice-bent ray from the path it would have taken without the glass in the way. What is this distance (in cm)? cm (e) At…