Consider two inputs A & B for a half adder. In such case, the sum can be obtained by O A OR B A XOR B None of the given options O A NAND B
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- This is the question: Suppose that we want to synthesize a circuit that has two switches x and y. The required functional behavior of the circuit is that the output must be equal to 0 if switch x is opened (x=0 ) and y is closed (y=1); otherwise the output must be 1. My friend sent me the answer which I will attach but I have no idea what is going on .. can someone please explain in detail?Using the truth table below ( An example sum-of-products expression is (A+B+C)(A+B+C')(A+B'+C)(A'+B+C).) a. Write a product-of-sums Boolean expression bexp4 for the output ? of the truth table b. Draw a circuit that is a direct translation of bexp4 without any simplification. For the circuit, use a layout that is analogous to the layout of the sample circuit below (where the and and or gates are appropriately swapped).Implement using Multiplexer 8:1 with residual variable. Please draw it using the logic gates, the circuit diagram. Do not draw the multiplexer chip per se. F=min(1,4,5,13,14,15)
- Draw a circuit that implements a 3-bit Adder that takes two 3-bit numbers as input, each on 3 input lines and outputs a 4 bit number on 4 output lines. You may use the Half Adder, the Full Adder and the following gates: NOT, AND, OR, XOR. Make sure to clearly label the interface wires on your diagram and the types of gates you use.Use muxes to implement various gates. In each circuit, draw the specified number of 2:1 muxes and implement the given boolean expression. A mux input can be A, B, 0, 1, or the output of another device (e.g., another mux or a decoder). Be sure to label the S, 0, and 1 inputs of every mux. a. Use one 2:1 mux to implement NOT A (i.e. A') b. Use one 2:1 mux to implement A AND B (i.e. AB) c. Use one 2:1 mux to implement A OR B (i.e. A+B)The circuit of Exp #8.2, configured as a subtractor, can be used to compare two 4-bit numbers. Subtractor outputs Cout and (S3.so) can be combined logically to indicate the relationship between inputs A and B. The gate circuit needed to do this appears as the interface block in the following diagram. Subtractor 220 ohm Cout A - B LEDO 4 A S3 A < B LED1 220 ohm Interface Block S2 (Your Design) 220 ohm B S1 A > B LED2 So (A - B) AirSupplyLab.com Figure 8.2: 4-bit Comparator Design the contents of this interface. You will build the circuit using only 2 chips: 1. a 7402 NOR chip 2. either a 7432 OR chip or a 7408 AND chip. Design the interface two ways: (a) an OR and NOR circuit, and (b), a NOR and AND circuit. Include both designs in your lab notebook and build and test one of them. Each design consists of 3 parts – one for each output – and requires 5 gates total. ExpressSCH has custom DM symbols for all gates (including ANDS and ORs). Use them, but only where they make circuit…
- This is a Verilog HDL, a subject in Computer Engineering. Based from Drill1_1 as per stated on the screenshot, notice that wire1, wire2, and wire3 are outputs of gates EOR2, NOT and AND2 Why are they declared as wire instead of output?Assume we are writing a testbench for a sequential circuit that has three control inputs (cA, cB, cC) and a periodic clock (clk). If we define CLK_PERIOD as a localparameter with a value of 50 (nsec), write the testbench segment that would ensure all possible combinations of the control inputs were tested on a clock rising edge. This is can be done more elegantly if you define each time step in terms of the constant CLK_PERIOD. Your answer should include the statements that define clk, cA, cB, and cC over time. Hint: think of how you would show all combinations of three variables on a truth table and replicate that over time, where each combination is held over a timespan with a clock triggering edge.Create a logic circuit using only basic gates such as AND, OR, NOR, NAND, NOT, etc. to implement a Subtractor that is capable of subtracting the second number from the first, by converting the second number into its 2's complement form and then adding the resulting number to the first number. You do not need to worry about accomodating the addition or subtraction of negative numbers. Also, create a limited ALU (Arithmetic logic unit) circuit using Logism that implements a Full Adder circuit capable of adding 2 – 4 bit binary numbers and subtracting 2- 4 bit binary numbers. Also, implement the ability to select a bitwise AND operation and a bitwise OR operation. For the ALU it is acceptable to use the Adder and Subtractor circuits that are listed under the "Arithmetic" folder in Logism. (Logism tips and tricks are useful here for multi-bit pins, and how to set up different gates to support more than 1 bit. If using YOUR adder or subtractor circuit in your ALU that is not only acceptable…
- The input of an IC requires a constant 5 V, but the supply voltage is 9 V. Use thevoltage divider equations to create a voltage divider with an output of 5 V. Assumethe IC has such a high input resistance (10 MΩ) that it practically draws nocurrent from the divider.subject: Digital Logic &Design Q: For the 4-input multiplexer, data inputs are givenas: D0 = 0, D1 = 1, D2 = 0, D3 = 1Find the output Y if the select inputs are given as:a)S0 = 1, S1 = 0b)S0 = 0, S1 = 1c)S0 = 1, S1 = 1d)S0 = 0, S1 = 0Using logic gates, design a circuit that has a capability to perform 4 bit binary addition orsubtraction based on the choice of the user. The circuit should accept decimal numbers from the users andthe sum will be displayed in a seven segment. Test the designed circuit in a simulation and submitscreenshots of sample inputs and outputs. Include in your submission your KMAP Solutions, truth tablesand sample manual calculations.