Consider using the method of partial fractions to solve dx x²+x+1 2x²+2+x³+x - dx = [Aƒ (x) − B ln(g(x))] + D ſb da, and if A = ‚B<0, then g(x) = x+2 x² +1 In(x²) In(x²+1) x + 2

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A: a)AB=2-2-235-32-1AB=2(5)-2(2)2(-3)+2-2(5)+3(2)-2(-3)-3AB=10-4-6+2-10+66-3AB=[6-4-43]A-1=1AAdj(A)A-1=…

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A: Let's find.

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A: Since you have asked multiple question, we will solve the first question for you as per our guide…

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A: Let's find.

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A: To evaluate: I=∫x-2sec41xtan521xdx Substitute 1x=t⇒-1x2dx=dt⇒x-2=-dt So, I=∫sec4t  tan52t…

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Q: II. Find d Do not simplify your answers. 1. log,(√2x² + y) + tan(z* — x") = sin−¹(x² − 1) + ½

A: This question can be solved using the concept of differentiation of implicit function.

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A: Note: According to our guideline i didn't solved more than three subparts. So, please again repost…

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A: I am attaching image so that you understand each and every step.

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