Considering the chemical equation :below C2H3B13 + 11 O2 → 8 CO2 + 6 H20 + 4 6 Br2 What is the maximum amount of bromine (Br2) that can be obtained from mixing 38.2 g of C2H3BR3 with 24.6 g of O2 (Mw of C2H3B13 = 266.76 amu, O2 = ?(32.00 amu and Br2 = 159.81 amu %3D g 32.5 О g 34.4 O g 17.2 O g 12.5 O g 134 O

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Considering the chemical equation
:below
C2H3Br3 + 11 O2 → 8 CO2 + 6 H20 + 4
6 Br2
What is the maximum amount of
bromine (Br2) that can be obtained from
mixing 38.2 g of C2H3B13 with 24.6 g of
O2 (Mw of C2H3Br3 = 266.76 amu, O2 =
?(32.00 amu and Br2 = 159.81 amu
g 32.5 O
g 34.4 O
g 17.2 О
g 12.5 O
g 134 О
Transcribed Image Text:Considering the chemical equation :below C2H3Br3 + 11 O2 → 8 CO2 + 6 H20 + 4 6 Br2 What is the maximum amount of bromine (Br2) that can be obtained from mixing 38.2 g of C2H3B13 with 24.6 g of O2 (Mw of C2H3Br3 = 266.76 amu, O2 = ?(32.00 amu and Br2 = 159.81 amu g 32.5 O g 34.4 O g 17.2 О g 12.5 O g 134 О
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