Considering the chemical equationbelow4 KO2(s) + 2 H20(1) → 4 KOH(s) + 302(g)When 4.50 g of H20 was reacted, thepercent yield of oxygen was 73.2 %.What was the actual yield of oxygen?O a. 16.4 gO b. 3.90 gO c. 5.85 gO d. 8.77 gO e. 2.78 g

1. first we have to find theoretical yield 2. To find the percentage yield formula is…

Answered: Considering the chemical equation

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Considering the chemical equation

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 14CR

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Question

Considering the chemical equation
below
4 KO2(s) + 2 H20(1) → 4 KOH(s) + 3
02(g)
When 4.50 g of H20 was reacted, the
percent yield of oxygen was 73.2 %.
What was the actual yield of oxygen?
O a. 16.4 g
O b. 3.90 g
O c. 5.85 g
O d. 8.77 g
O e. 2.78 g

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