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Constants PeriodicA soccer player can kick the ball 30 m on level ground, withits initial velocity at 39 to the horizontal.Part AAt the same initial speed and angle to the horizontal, what horizontal distance can the player kick the ball on a 20upward slope?Express your answer using two significant figuresНАValueUnitsd =Previous AnswersRequest AnswerSubmit

Question
Constants Periodic
A soccer player can kick the ball 30 m on level ground, with
its initial velocity at 39 to the horizontal.
Part A
At the same initial speed and angle to the horizontal, what horizontal distance can the player kick the ball on a 20
upward slope?
Express your answer using two significant figures
НА
Value
Units
d =
Previous Answers
Request Answer
Submit
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Constants Periodic A soccer player can kick the ball 30 m on level ground, with its initial velocity at 39 to the horizontal. Part A At the same initial speed and angle to the horizontal, what horizontal distance can the player kick the ball on a 20 upward slope? Express your answer using two significant figures НА Value Units d = Previous Answers Request Answer Submit

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Step 1

Given:

Horizontal range = 30 m

Angle of projection = 39 degrees

Step 2

Calculating the initial velocity of the ball:

Caleulating the initial velocity of the ball
Let the velocity of the ball= u m/s
For the given projectile motion, the formula for range is,
u2sin20
R
(Where 'u' is the initial velocity)
Substitute R
30 m, 0 = 39° and g = 9.8 m/s2
u2sin (78)
30
9.8
30 X 9.8
sin(78°300.6
u 17.34 m/s
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Caleulating the initial velocity of the ball Let the velocity of the ball= u m/s For the given projectile motion, the formula for range is, u2sin20 R (Where 'u' is the initial velocity) Substitute R 30 m, 0 = 39° and g = 9.8 m/s2 u2sin (78) 30 9.8 30 X 9.8 sin(78°300.6 u 17.34 m/s

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Step 3

Finding the horizontal distance covered by ...

Let the horizontal distance covered by the ball on the upward slope x
Horizontal distance covered by the ball on the ground x cos(200) 0.94 x
Vertical distance covered by the ball
sin(20) 0.34 x
= X
Considering the vertical motion of ball upto hight 0.34 x:
can write
Using second equation of motion
we
17.34 sin(39°)(T)-;x
x 9.8 x (T)...(1)
0.34x
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Let the horizontal distance covered by the ball on the upward slope x Horizontal distance covered by the ball on the ground x cos(200) 0.94 x Vertical distance covered by the ball sin(20) 0.34 x = X Considering the vertical motion of ball upto hight 0.34 x: can write Using second equation of motion we 17.34 sin(39°)(T)-;x x 9.8 x (T)...(1) 0.34x

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