Convert the following Infix Expression to a Postfix Expression using stack. X * Y - K / M + (J * H) Data structures and algorithms
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A: To convert infix expression to postfix expression we will use the stack data structure.
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Convert the following Infix Expression to a Postfix Expression using stack.
X * Y - K / M + (J * H)
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- Evaluate the following (postfix) expression using a stack. Assume A=1, B = 2 and C = 3. ABC+*CBA-+*Look at this stack frame: Fill in the data types for the following procedure: SomeSub PROC, LOCAL val1: , LOCAL val2: , LOCAL val3: , LOCAL val4:algorithm data structure + (a * b / c) - d ^ e – f * g Convert the infix to postfix expression using stack data structure.
- Use C++ STL: Using a stack or a queue or a priority queue, create a program that reads an unordered list of integers and then displays the integers sorted in ascending order. Do not write or use a sorting algorithm.Convert the following expression from infix to postfix and show the contents of Stack and the output expression at each step ((A-((B+C)*D/E))/(F*G+H))Python code Use input data from input file Output the results in an output file You will use recursion to convert prefix expressions directly to postfix expressions. You may not use a stack as you did in Lab 1. Write a program that accepts a prefix expression containing single letter operands and the operators +, -, *, /, and $ (representing exponentiation). Output the corresponding postfix epression. Be sure to discuss why recursion makes sense. For example, if your input is *AB then output should be AB*. Output of BA* is considered incorrect. Required input file: -+ABC-A+BC$+-ABC+D-EF-*A$B+C-DE*EF**A+BC+C-BA/A+BC +C*BA *-*-ABC+BA /+/A-BC-BA *$A+BC+C-BA//A+B0-C+BA*$A^BC+C-BA Output file should produce for: Prefix = -+ABC AB+C- or Prefix = -A+BC ABC+- or Prefix = $+-ABC+D-EF $+-ABC+D-EF Thanks!
- Question 11 mah.c- Write a program to perform the following operations on a stack data structure. c.1 Create push and pop functions and display the items [12,9,3,25,19,0,5,30,9] after performing push and then pop operation. c.2 Write a function to convert an infix expression (2 – (1 / 5 ) * 6 + 12 ) * 33 % 9) to postfix expression and display the result. c.3 Applying best practices for writing code comments I want the code in c++ language Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this lineWrite a C code to dynamically construct an ordered list of characters. The code should have the following functionality: Add a node to the list (a Char type value) Remove a node from the list (a Char type value) Display to show the current list Quit from the program execution.The list should be ordered in ascending manner in terms of ASCII value of the char type inputs.Do not copy from chegg and do it in c++ Write a program to convert an infix expression to a postfix expression. Input: an infix expression Output: the corresponding postfix expression Note: You must use the stack to implement this task. And you can use any one of the above stack implementations. Test your program using the following expressions: (a + b) * c (a - b) / (c +d) (a*b+c/d)/e
- 4. a) Using the stack diagram, convert the following infix expression to a postfix expression. A + B / C * (D – E) b) Referring to question 4 (a), give the value of postfix expression by using the stack concept if provided: A=13, B=20, C=4, D=30, E=25Postfix using StacksThe rules to convert an infix expression into an equivalent postfix expression are as follows: Suppose infx represents the expression and pfx represents the postfix expression. The rules to convert infx into pfx are as follows: 1. Initialize pfx to an empty expression and also initialize the stack.2. Get the next symbol, sym, from infx. a. if sym is an operand, append sym to pfx b. if sym is (. push sym into the stack. c. if dym is ). pop snd append all the symbols from the stack until the most recent left parenthesis. Pop and discard the left parentheses. d. If sym is an operator: i. Pop and append all of the operators from the stack to pfx that are above the most recent left parenthesis and have precededence greater than or equal to sym ii. Push sym onto the stack. 3. After processing infx, some operators might be left in the stack. Pop and append to pfx everything from the stack. In this program, you will…(C Language) The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the Fibonacci() function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1.