Cooler Control Warmer 1.59 1.92 2.57 1.43 2.00 2.60 1.88 2.19 1.93 1.26 1.12 1.58 1.91 1.78 2.30 1.86 1.84 0.84 1.90 2.45 2.65 1.57 2.03 0.07 1.79 1.52 2.74 1.72 0.52 2.53 2.41 1.90 2.13 2.34 2.86 0.87 2.31 1.34 1.91 1.76 (a) Compare measures of center for the three different samples. Cooler Control Warmer

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An article described an experiment in which observations on various characteristics were made using minichambers of three different types: (1) cooler (PVC frames covered with shade cloth), (2) control (PVC frames only), and (3) warmer (PVC frames covered with
plastic). One of the article's authors kindly supplied the accompanying data on the difference between air and soil temperatures (°C).
Cooler
Control
Warmer
1.59
1.92
2.57
1.43
2.00
2.60
1.88
2.19
1.93
1.26
1.12
1.58
1.91
1.78
2.30
1.86
1.84
0.84
1.90
2.45
2.65
1.57
2.03
0.07
1.79
1.52
2.74
1.72
0.52
2.53
2.41
1.90
2.13
2.34
2.86
0.87
2.31
1.34
1.91
1.76
(a) Compare measures of center for the three different samples.
Cooler
Control
Warmer
(b) Calculate the standard deviations for the three different samples. (Round your answers to three decimal places.)
Cooler
S =
%3=
Control
Warmer
S =
Interpret and compare the standard deviations for the three different samples.
O we see from the standard deviations that variability increases as the conditions of the minichambers transition from warmer to cooler.
O we see from the standard deviations that variability increases as the conditions of the minichambers transition from cooler to warmer.
O we see from the standard deviations that variability increases when the conditions of of the mini-chambers transitions from the cooler to the control and decreases when the conditions transition from the control to warmer.
O we see from the standard deviations that variability decreases as the conditions of the minichambers transition from cooler to warmer.
O we see from the standard deviations that there is no difference in variability between the three conditions.
Transcribed Image Text:An article described an experiment in which observations on various characteristics were made using minichambers of three different types: (1) cooler (PVC frames covered with shade cloth), (2) control (PVC frames only), and (3) warmer (PVC frames covered with plastic). One of the article's authors kindly supplied the accompanying data on the difference between air and soil temperatures (°C). Cooler Control Warmer 1.59 1.92 2.57 1.43 2.00 2.60 1.88 2.19 1.93 1.26 1.12 1.58 1.91 1.78 2.30 1.86 1.84 0.84 1.90 2.45 2.65 1.57 2.03 0.07 1.79 1.52 2.74 1.72 0.52 2.53 2.41 1.90 2.13 2.34 2.86 0.87 2.31 1.34 1.91 1.76 (a) Compare measures of center for the three different samples. Cooler Control Warmer (b) Calculate the standard deviations for the three different samples. (Round your answers to three decimal places.) Cooler S = %3= Control Warmer S = Interpret and compare the standard deviations for the three different samples. O we see from the standard deviations that variability increases as the conditions of the minichambers transition from warmer to cooler. O we see from the standard deviations that variability increases as the conditions of the minichambers transition from cooler to warmer. O we see from the standard deviations that variability increases when the conditions of of the mini-chambers transitions from the cooler to the control and decreases when the conditions transition from the control to warmer. O we see from the standard deviations that variability decreases as the conditions of the minichambers transition from cooler to warmer. O we see from the standard deviations that there is no difference in variability between the three conditions.
Expert Solution
Step 1

Part (a)

The measures of the center is generally calculated by taking mean and median.

Express the given characteristics of cooler in numerical order.

0.87,1.26,1.34,1.43,1.57,1.59,1.72,1.76,1.79,1.86,1.88,1.90,1.91,2.34,2.41.

Since, it contains 15 elements. The median is n+12th  value.

Median=8th value=1.76

 

Step 2

Express the given characteristics of control in numerical order.

0.52,1.12,1.52,1.78,1.84,1.90,1.92,2.00,2.03,2.19,2.45.

Since, it contains 11 elements. The median is n+12th  value.

Median=6th value=1.90

So, the center value is 1.90.

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