Copy DataThe estimated regression line and the standard error are given.Defects per Countertop = 6.717822 – 1.004950(Hours of TrainingSe = 1.229787Suppose a new employee has had 9 hours of training. What would be the 99 % prediction interval for the number of defects per countertop? Round your answer totwo decimal places.AnswerKeypadKeyboard ShortcutsTablesIfM A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employeereceives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received isrecorded and the number of defects on the most recent countertop produced is determined. The results are as follows.Copy DataHours of Training1473225er516Defects per Countertop5103541282dfIfM

Number of employees selected=10 Confidence interval=99%

Copy Data The estimated regression line and the standard error are given. Defects per Countertop= 6.717822-1.004950(Hours of Training Se = 1.229787 Suppose a new employee has had 9 hours of training. What would be the 99 % prediction interval for the number of defects per countertop? Round your answer to two decimal places. Answer Keypad Keyboard Shortcuts Tables

Copy Data The estimated regression line and the standard error are given. Defects per Countertop= 6.717822-1.004950(Hours of Training Se = 1.229787 Suppose a new employee has had 9 hours of training. What would be the 99 % prediction interval for the number of defects per countertop? Round your answer to two decimal places. Answer Keypad Keyboard Shortcuts Tables

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section11.4: Collecting Data

Problem 6E

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