/* * copyLSB - set all bits of result to least significant bit of x * Example: copyLSB(5) = 0xFFFFFFFF, copyLSB(6) = 0x00000000 * Legal ops: ! ~ & ^ | + << >> * Max ops: 5 * Rating: 2 */ int copyLSB(int x) { return 2; }
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/*
* copyLSB - set all bits of result to least significant bit of x
* Example: copyLSB(5) = 0xFFFFFFFF, copyLSB(6) = 0x00000000
* Legal ops: ! ~ & ^ | + << >>
* Max ops: 5
* Rating: 2
*/
int copyLSB(int x) {
return 2;
}
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- implement greatestBitPos function Compute a mask marking the most significant 1 bit. you are only allowed to use the following eight operators: ! ~ & ^ | + << >> “Max ops” field gives the maximum number of operators you are allowed to use to implement each function /* * greatestBitPos - return a mask that marks the position of the* most significant 1 bit. If x == 0, return 0* Example: greatestBitPos(96) = 0x40* Legal ops: ! ~ & ^ | + << >>* Max ops: 70* Rating: 4 */int greatestBitPos(int x) {return 2;}Computer Science Is it possible to convert this to java? #include <stdio.h> void printBinary(int n, int i) { // Prints the binary representation // of a number n up to i-bits. int k; for (k = i - 1; k >= 0; k--) { if ((n >> k) & 1) printf("1"); else printf("0"); } } typedef union { float f; struct { // Order is important. // Here the members of the union data structure // use the same memory (32 bits). // The ordering is taken // from the LSB to the MSB. unsigned int mantissa : 23; unsigned int exponent : 8; unsigned int sign : 1; } raw; } myfloat; // Function to convert real value // to IEEE floating point representation void printIEEE(myfloat var) { // Prints the IEEE 754 representation // of a float value (32 bits) printf("%d | ", var.raw.sign);…implement anyEvenBit(x) Return 1 if any even bit in x is set to 1 you are only allowed to use the following eight operators: ! ~ & ^ | + << >> “Max ops” field gives the maximum number of operators you are allowed to use to implement each function /* * anyEvenBit - return 1 if any even-numbered bit in word set to 1* Examples anyEvenBit(0xA) = 0, anyEvenBit(0xE) = 1* Legal ops: ! ~ & ^ | + << >>* Max ops: 12*/int anyEvenBit(int x) {return 2;}
- In Java This assignment introduces bitwise-manipulation operators (&, |, <<, >>, >>>, ^, and ~),which are not discussed elsewhere in the book. The bitwise-manipulation operators performsimultaneous bit manipulations and enable programs to process large quantities of binaryinformation efficiently. This project is here because the solution uses a conditional operator.The binary & and | operators can implement bitwise “and” and “or” operations oncorresponding bits in a pair of 32-bit int operands. This bit-manipulation capability enablesJava to efficiently process large quantities of raw binary information. We use this capability toencrypt information sent over the Internet and to process graphical images. Suppose you havea 32-bit pattern of 1’s and 0’s in an integer called mask. You can use mask to either set to 1or reset to 0 any subset of the bits in another integer called data:• data |= mask;1 drives to 1 all bits in data that correspond to 1 bits in…/* segvhunt.cFind and eliminate all code that generates Segmentation Fault*/#include <stdio.h>int main() {char **s;char foo[] = "Hello World";*s = foo;printf("s is %s\n",s);s[0] = foo;printf("s[0] is %s\n",s[0]);return(0);}* Assignment: Word operations * * Description: * This assignment asks you to implement common word operations that are * not available in the Scala programming language. The intent is to practice * your skills at working with bits. * */ package wordOps /* * Task 1: Population count (number of 1-bits in a word) * * Complete the following function that takes as parameter * a 32-bit word, w, and returns __the number of 1-bits__ in w. * */ def popCount(w: Int): Int = ??? /* * Task 2: Reverse bit positions * * Complete the following function that takes as parameter * a 16-bit word, w, and returns a 16-bit word, r, such that * for every j=0,1,...,15, * the value of the bit at position j in r is equal to * the value of the bit at position 15-j in w. * */ def reverse(w: Short): Short = ??? /* * Task 3: Left rotation * * Complete the following function that takes two parameters * * 1) a 64-bit word, w, and *…
- #include<stdio.h> #define FAIL_VAL -99999#define SUCCESS_VAL 99999#define MAX_USER 20#define MAX_LEN 200 char emailArr[MAX_USER][MAX_LEN];char passArr[MAX_USER][MAX_LEN]; char nameArr[MAX_USER][MAX_LEN];char addressArr[MAX_USER][MAX_LEN]; int user_count=0; int signupUser(char email[], char pass[]){ char Email_id[60]; int i;//p1=0,p2=0; printf("Enter your Email_id: "); scanf("%s", &Email_id); if(Email_id[i]=='@' && Email_id[i]=='.') { printf("Your Email_id is valid"); } else { printf("Email_id invalid.Please enter a valid id."); } } int loginUser(char email[], char pass[]){ //Write your code here} int buildUserProfile(char email[], char firstName[], char lastName[], char address[]){ //Write your code here} void searchByName(char name[]){ //Write your code here} void searchByAddress(char address[]){ //Write your code here} int main(){ while(1) {…#include<stdio.h> #define FAIL_VAL -99999#define SUCCESS_VAL 99999#define MAX_USER 20#define MAX_LEN 200 char emailArr[MAX_USER][MAX_LEN];char passArr[MAX_USER][MAX_LEN]; char nameArr[MAX_USER][MAX_LEN];char addressArr[MAX_USER][MAX_LEN]; int user_count=0; int signupUser(char email[], char pass[]){char Email_id[60];int i;//p1=0,p2=0;printf("Enter your Email_id: ");scanf("%s", &Email_id); if(Email_id[i]=='@' && Email_id[i]=='.'){printf("Your Email_id is valid");}else{printf("Email_id invalid.Please enter a valid id.");} } int loginUser(char email[], char pass[]){//Write your code here} int buildUserProfile(char email[], char firstName[], char lastName[], char address[]){//Write your code here} void searchByName(char name[]){//Write your code here} void searchByAddress(char address[]){//Write your code here} int main(){while(1){printf("*******************************************************************\n");printf("1. signup User. 2. login User. 3. build User Profile.…#include<stdio.h> #define FAIL_VAL -99999#define SUCCESS_VAL 99999#define MAX_USER 20#define MAX_LEN 200 char emailArr[MAX_USER][MAX_LEN];char passArr[MAX_USER][MAX_LEN]; char nameArr[MAX_USER][MAX_LEN];char addressArr[MAX_USER][MAX_LEN]; int user_count=0; int signupUser(char email[], char pass[]){char Email_id[60];int i;//p1=0,p2=0;printf("Enter your Email_id: ");scanf("%s", &Email_id); if(Email_id[i]=='@' && Email_id[i]=='.'){printf("Your Email_id is valid");}else{printf("Email_id invalid.Please enter a valid id.");} } int loginUser(char email[], char pass[]){//Write your code here} int buildUserProfile(char email[], char firstName[], char lastName[], char address[]){//Write your code here} void searchByName(char name[]){//Write your code here} void searchByAddress(char address[]){//Write your code here} int main(){while(1){printf("*******************************************************************\n");printf("1. signup User. 2. login User. 3. build User Profile.…
- #include<stdio.h> #define FAIL_VAL -99999#define SUCCESS_VAL 99999#define MAX_USER 20#define MAX_LEN 200 char emailArr[MAX_USER][MAX_LEN];char passArr[MAX_USER][MAX_LEN]; char nameArr[MAX_USER][MAX_LEN];char addressArr[MAX_USER][MAX_LEN]; int user_count=0; int signupUser(char email[], char pass[]){ char Email_id[60]; int i;//p1=0,p2=0; printf("Enter your Email_id: "); scanf("%s", &Email_id); if(Email_id[i]=='@' && Email_id[i]=='.') { printf("Your Email_id is valid"); } else { printf("Email_id invalid.Please enter a valid id."); } } int loginUser(char email[], char pass[]){ //Write your code here} int buildUserProfile(char email[], char firstName[], char lastName[], char address[]){ //Write your code here} void searchByName(char name[]){ //Write your code here} void searchByAddress(char address[]){ //Write your code here} int main(){ while(1) {…Not pseudocode Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [We are expecting a description of the algorithm, as well as a brief justification of its runtime.]implement byteSwap(x,n,m) Swap the m and n byte of x /* * byteSwap - swaps the nth byte and the mth byte* Examples: byteSwap(0x12345678, 1, 3) = 0x56341278* byteSwap(0xDEADBEEF, 0, 2) = 0xDEEFBEAD* You may assume that 0 <= n <= 3, 0 <= m <= 3* Legal ops: ! ~ & ^ | + << >>* Max ops: 25*/ int byteSwap(int x, int n, int m) {return 2;}
