cosx+1=sinx

Q: Differentiate (sinx)2(sin-1x)2

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Q: Cos x sin (sinx) dx

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Q: Hlim X-3 Sinx X->o

A: Given : limx→0x2-3sinxx

Q: 2 cosx+3 cosx=2, 0Sx<27

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Q: Differentiate y=(1-cosx)/sinx

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Q: 12 sinx Cos X=

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Q: Differentiate sin x +1

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Q: 12.y = sin(tanx) 13.y = 2sinxcosx cosx 14.y = x2 tanx 15.y = sinx

A: We have to find derivative

Q: - 2 Sinx), sin4x dx

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Q: Calculate 7² ( sin³ r) dx /2

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Q: sin S S. cossx (3-2secs)

A: The given integral is ∫sin 5xcos2(5x)3-2sec(5x)dx The derivative formula is ddx(sec ax)=atan…

Q: 2- cusx dx COSX Sinx +2 Sinx t5

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Q: integrate sin(x)

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Q: | cos ) sin(x) dx

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Q: Simplify: cosx sec x – cos² x O cos² x sec x sin x

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Q: inetgrate sin^2(x)csc^2(2x)

A: Given: Let I=∫sin2xcsc22xdx To Find: To integrate the given integration.

Q: If tanx = (a/b) find the value of (cosx+sinx)/(cosx-sinx)

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Q: Solve Sinx Cos2y дхду

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Q: Differentiate Sin (m sin-1 x)

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Q: Evaluate sin2xlogtanx dx 0.

A: We will evaluate the definite intrgral as following.

Q: Simplify. sin 2x · cos 3x – cos 2x · sin 3x

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Q: ∫(sinx+sinxtan^2x)/sec^2x dx on the domain [0,π/3]

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Q: Differentiate y=(sinx)2(sin-1x)2

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Q: | sin³(18x) dx =

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Q: Differentiate Sin(x2 +1)

A: Differentiate   Sin(x^2 +1)

Q: Sinx cosx =    1/3          0≤x&lt;2π

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Q: Is Cscx-1/1-Sinx=cscx

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Q: Evaluate tan (3x+1) sec³(3x+1) dx

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Q: *cosx= 24 sinxyo, cos (x+5") 25

A: Given: cosα=2425, sinα&gt;0 To determine: cosα+5π6

Q: cos² (x) sin (x) dx

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Q: ) Evaluate cosx sinx V1 – sin4x dx.

A: Use substitution method to solve this

Q: tan x dx sec x+4 cosx 5.

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Q: Evaluate the integral.

A: Given integral is ∫sin2xdx1+cos2x. Consider a=1+cos2x. Then da=-2cosxsinxdxdx=da-sin2x

Q: Solve sin x − cos x = 1 if 0 ≤ x ≤ 2π.

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Q: Integrate cosx cos (x-a)

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Q: cosx = secx-sinx tanx %3D

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Q: Evaluate | sin2x tan (sinx)dx

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Q: cos dx 5. Vaš sin² 3

A: Consider the integral: I=∫cos6x23dxx25sin23x23

Q: Differentiate sin√(x/x+8).

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Q: Find Dx (sin4 x).

A: we have to find the value of Dxsin4x

Q: Differentiate  cosx/x

A: The given function is f(x) =(cosx)/x       = x-1.cosx

Q: tantx + CosX-Stcx = SeC %3D COSX

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Q: dx sec5x(3+sin5х)

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Q: + Sin (2x) de

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Q: 6 sinx (cosx + 1)5 dx

A: We will find the value of definite integral as following.

Q: sinx dx (cosx)2+cosx-2

A: Use substitution method:  Substitute cosx =t

Q: 12. cosx(1+ tanx)² = secx + 2sinx %3D

A: Prove : cosx ( 1 + tanx)^2 = secx + 2 sinx

Q: | sin5 cos cos – dx 3

A: The given integral is ∫sin5x3cosx3dx

Q: 1 Cosx %3D secx+1 COSx+1

A: As per our guidelines we are supposed to answer only one question.Kindly repost other question as…