count=10; maphore Lock=1; // initial value is 1 read1(...) // do something Lock.Wait(); count++; Lock Signal();

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Suppose a program P has the following three threads Thread1, Thread2, and
Thread3, and a shared counter, count, as shown below:
int count = 10;
Semaphore Lock = 1; // initial value is 1
Thread1(...)
(
1
Thread2(...)
{
}
// do something
Lock. Wait();
count++;
Lock.Signal();
{
// do something
Lock. Wait();
count-
Lock.Signal();
Thread3(...)
// do something
Lock. Wait();
printf("%d", count);
Lock Signal();
Upon the execution of the program P, the number of possible orders of
execution of threads where the output will be 10 is
Note: The above three threads are non-preemptive threads.
Transcribed Image Text:Suppose a program P has the following three threads Thread1, Thread2, and Thread3, and a shared counter, count, as shown below: int count = 10; Semaphore Lock = 1; // initial value is 1 Thread1(...) ( 1 Thread2(...) { } // do something Lock. Wait(); count++; Lock.Signal(); { // do something Lock. Wait(); count- Lock.Signal(); Thread3(...) // do something Lock. Wait(); printf("%d", count); Lock Signal(); Upon the execution of the program P, the number of possible orders of execution of threads where the output will be 10 is Note: The above three threads are non-preemptive threads.
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