Create a function set(v, i, j) that makes vector v contain the integers i through j. The original contents of v is deleted. The vector is left empty if j < i. The argument v is a vector of integers
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Create a function set(v, i, j) that makes
j < i. The argument v is a vector of integers.
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- C++ Create a function set(v, i, j) that makes vector v contain the integers i through j. The original contents of v is deleted. The vector is left empty ifj < i. The argument v is a vector of integers.Write a function named addStars that accepts as a parameter a reference to a vector of strings, and modifies the vector by placing a "*" element between elements, as well as at the start and end of the vector. For example, if the vector v contains {"the", "quick", "brown", "fox"}, the call of addStars(v); should modify it to store {"*", "the", "*", "quick", "*", "brown", "*", "fox", "*"}.Create a function append(v, a, n) that adds to the end of vector v a copy of all the elements of array a. For example, if v contains 1,2, 3, and a contains 4, 5, 6, then v will end up containing 1, 2, 3, 4, 5,6. The argument n is the size of the array. The argument v is a vector ofintegers and a is an array of integers. Write a test driver.
- Define a function named GetWordFrequency that takes a vector of strings and a search word as parameters. Function GetWordFrequency() then returns the number of occurrences of the search word in the vector parameter (case insensitive). Then, write a main program that reads a list of words into a vector, calls function GetWordFrequency() repeatedly, and outputs the words in the vector with their frequencies. The input begins with an integer indicating the number of words that follow. Ex: If the input is: 5 hey Hi Mark hi mark the output is: hey 1 Hi 2 Mark 2 hi 2 mark 2 Hint: Use tolower() to set the first letter of each word to lowercase before comparing. The program must define and use the following function:int GetWordFrequency(vector<string> wordsList, string currWord) write code in c++Define a function named GetWordFrequency that takes a vector of strings and a search word as parameters. Function GetWordFrequency() then returns the number of occurrences of the search word in the vector parameter (case insensitive). Then, write a main program that reads a list of words into a vector, calls function GetWordFrequency() repeatedly, and outputs the words in the vector with their frequencies. The input begins with an integer indicating the number of words that follow. Ex: If the input is: 5 hey Hi Mark hi mark the output is: hey 1 Hi 2 Mark 2 hi 2 mark 2 Hint: Use tolower() to set the first letter of each word to lowercase before comparing. The program must define and use the following function:int GetWordFrequency(vector<string> wordsList, string currWord)Write a function named cumulative that accepts as a parameter a reference to a vectorof integers, and modifies it so that each element contains the cumulative sum of the elements up through that index. For example, if the vector passed contains {1, 1, 2, 3, 5}, your function should modify it to store {1, 2, 4, 7, 12}.
- In c++ please Write the RemoveEvens() function, which receives a vector of integers as a parameter and returns a new vector of integers containing only the odd numbers from the original vector. The main program outputs values of the returned vector. Hint: If the original vector has even numbers, then the new vector will be smaller in length than the original vector and should have no blank element. Ex: If the vector passed to the RemoveEvens() function is [1, 2, 3, 4, 5, 6, 7, 8, 9], then the function returns and the program output is: [1, 3, 5, 7, 9] Ex: If the vector passed to the RemoveEvens() function is [1, 9, 3], hen the function returns and the program output is: [1, 9, 3] #include <iostream>#include <vector>using namespace std; vector<int> RemoveEvens(vector<int> nums) { /* Type your code here */} int main() { vector<int> input(9); input.at(0) = 1; input.at(1) = 2; input.at(2) = 3; input.at(3) = 4; input.at(4) = 5;…Modify your bottom-up function DPchange to return not only the best number of coins but also the corresponding combination of denominations as a vector. Do this by creating a new function DPChange_bt that is largely the same as DPChange but declares an array coinsUsed that keeps track of the coin on the best path to a given entry M (between 1 and ?+1). DPChange_bt should return both bestNumCoins and coinsUsed.Write a function that accepts a number, N, and a vector of numbers, V. The function will return two vectors which will make up any pairs of numbers in the vector that add together to be N. Do this with nested loops so the the inner loop will search the vector for the number N-V(n) == V(m). n and m are indices in the vector of numbers. Example A = [1,2,3,4,5,6, 7] Google(5, A) Return [1,2,3,4] and [4,3,2,1] being the pairs that sum to 5. Notice that each pair appears twice. Try to write code that does not do this.
- Define a function named SortVector that takes a vector of integers as a parameter. Function SortVector() modifies the vector parameter by sorting the elements in descending order (highest to lowest). Then write a main program that reads a list of integers from input, stores the integers in a vector, calls SortVector(), and outputs the sorted vector. The first input integer indicates how many numbers are in the list. Ex: If the input is: 5 10 4 39 12 2 the output is: 39,12,10,4,2, For coding simplicity, follow every output value by a comma, including the last one. Your program must define and call the following function:void SortVector(vector<int>& myVec)Write a function call Occurrence that receives two arguments: an array of vectors (generic type) and a generic variable called _item. The function returns the index of the vector (i.e. the index of the vector in the array of vectors) that has the highest occurrence of the item. The function returns -1 if the element ( item) is not found on any vector.C++ please help I will give you a good rating!!!!! Implement the following function that returns a vector of vectors of Item, each of which is a subset of elements chosen from the given vector a[first…last]: /* if a is {1,2,3}, first=0, last=2, the function shall returns a vector of the following vectors: {}, {1}, {2}, {3}, {1,2},{1,3}, {2,3},{1,2,3}, all subsets of a[0…2]. Precondition: last-first+1>=1, i.e., there is at least one element in the a[first…last] Note 1)if the length of a[first…last] is n, then the function should return a vector of 2n vectors 2) The order of these subsets does not need to match what’s listed here… */ vector<vector<int>> subsets (const vector<int> & a, int first, int last) CODE: #include <iostream> #include <algorithm> #include <vector> using namespace std; void PrintVector (const vector<int> & v){ cout <<"["; for (auto e:v){ cout<<e<<" "; } cout <<"]"; } /*…