Create table Medicine (MInventory_Id int primary key, M_Name varchar (40), Manufacturer varchar (40), Price varchar (20), Quantity int, Exp_Date date); Create table PrescriptionMedicine (Prescription_Id int primary key, MInventory_Id int); Example of a table (Medicine) Insert into Medicine values(101, ‘Biaxin’, ‘Pfizers’, ‘$10.99’, 1, 10/5/02);

Create table Medicine (MInventory_Id int primary key, M_Name varchar (40), Manufacturer varchar (40), Price varchar (20), Quantity int, Exp_Date date); Create table PrescriptionMedicine (Prescription_Id int primary key, MInventory_Id int); Example of a table (Medicine) Insert into Medicine values(101, ‘Biaxin’, ‘Pfizers’, ‘$10.99’, 1, 10/5/02);

Np Ms Office 365/Excel 2016 I Ntermed

1st Edition

ISBN:9781337508841

Author:Carey

Publisher:Carey

Chapter5: Working With Excel Tables, Pivottables, And Pivotcharts

Section: Chapter Questions

Problem 3.9CP

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MySql Workbench CREATE TABLE students ( id INT PRIMARY KEY, first_name VARCHAR(50), last_name VARCHAR(50), age INT, major VARCHAR(50), faculty VARCHAR(50)); CREATE TABLE location ( id INT PRIMARY KEY, name VARCHAR(50), rooms INT); CREATE TABLE faculty ( id INT PRIMARY KEY, name VARCHAR(50), department_id INT); 1. List last name of all students whose first name is longer than 4 letters in ascending order accordingto the last name. Duplicated rows should be removed from the output.2. Count the total number of rooms in Location.3. Find the number of students in each major.4. Find the number of employees in each department who get no commission or have salary less than5000.5. Find the maximum salary of employees in each department that the employee was hired 15 yearsbefore now. *hint: user TIMESTAMPDIFF(<unit type>,<Date_value 1>,<Date_value 2>), the unitcan be YEAR, MONTH, DAY, HOUR, etc...
CREATE TABLE employees8(employee_id NUMBER(10) PRIMARY KEY,first_name VARCHAR(25) UNIQUE,last_name VARCHAR(25) UNIQUE,job_id NUMBER(3),salary NUMBER(6) NOT NULL,department_name VARCHAR2(20));CREATE TABLE jobs8(job_id NUMBER(3) PRIMARY KEY,job_title VARCHAR2(25),min_salary NUMBER(4)check(min_salary >=2900),max_salary NUMBER(6)check(max_salary<=100000)); CREATE TABLE departments8(department_id NUMBER(2) PRIMARY KEY,department_name VARCHAR2(30),location_name VARCHAR2(15) DEFAULT 'Istanbul'); how can I do this question according to these 3 tables ? Create a complex view that joining with three tables.
CREATE TABLE MOVIE( mov_id int NOT NULL, mov_title varchar(255) NOT NULL, mov_releaseDate date, gen_id int NOT NULL, PRIMARY KEY (mov_id), FOREIGN KEY (gen_id) REFERENCES GENRE(gen_id) ); CREATE TABLE GENRE( gen_id int NOT NULL, PRIMARY KEY (gen_id), gen_name varchar(255) NOT NULL ); Search movies by year. Using the tables above, create a stored procedure, called getMovieByYear, that, given a year, returns all the movies which were released in that year. It displays the movie title, movie’s genre name, and release year.please use MySQL Workbench with screenshots of it for the explanation.
CREATE TABLE MOVIE( mov_id int NOT NULL, mov_title varchar(255) NOT NULL, mov_releaseDate date, gen_id int NOT NULL, PRIMARY KEY (mov_id), FOREIGN KEY (gen_id) REFERENCES GENRE(gen_id) ); CREATE TABLE GENRE( gen_id int NOT NULL, PRIMARY KEY (gen_id), gen_name varchar(255) NOT NULL );Search movies by year. Using the tables above, create a stored procedure, called getMovieByYear, that, given a year, returns all the movies which were released in that year. It displays the movie title, movie’s genre name, and release year.
CREATE TABLE MOVIE( mov_id int NOT NULL, mov_title varchar(255) NOT NULL, mov_releaseDate date, gen_id int NOT NULL, PRIMARY KEY (mov_id), FOREIGN KEY (gen_id) REFERENCES GENRE(gen_id) ); CREATE TABLE GENRE( gen_id int NOT NULL, PRIMARY KEY (gen_id), gen_name varchar(255) NOT NULL );EXTRACT YEAR. Using the tables above, create a query that returns all the rows from the movie table and displays the movie id, movie title, and movie’s release year (not the full date). Must provide screenshots of the resulting table.
create table patients ( patient_id VARCHAR(255),name VARCHAR(255),insurance DECIMAL(15,2),date_admitted DATE,date_checked_out DATE,PRIMARY KEY(patient_id));INSERT INTO patients (ID , name , insurance , date_admitted , date_checked_out) values (2 , 'Ali' , '22.2' , '2/1/2020' , '3/1/2020')SELECT * FROM table patients create table doctor (doctor_id VARCHAR(255),name VARCHAR(255),specialization VARCHAR(255),PRIMARY KEY (doctor_id) ); create table test (test_id VARCHAR(255),test_name VARCHAR(255),test_date DATE,test_time TIME,result VARCHAR(255),PRIMARY KEY(test_id)); create table doctor_patient( patient_id VARCHAR(255), doctor_id VARCHAR(255),PRIMARY KEY(patient_id),FOREIGN KEY(doctor_id) REFERENCES doctor(doctor_id) ); create table test_log (test_log_id varchar(255),patient_id VARCHAR(255),test_id VARCHAR(255),doctor_id VARCHAR(255),comments VARCHAR(255),PRIMARY KEY(test_log_id),FOREIGN KEY(test_id) REFERENCES test(test_id),FOREIGN KEY(patient_id) REFERENCES…
create table patients ( patient_id VARCHAR(255),name VARCHAR(255),insurance DECIMAL(15,2),date_admitted DATE,date_checked_out DATE,PRIMARY KEY(patient_id));INSERT INTO patients (ID , name , insurance , date_admitted , date_checked_out) values (2 , 'Ali' , '22.2' , '2/1/2020' , '3/1/2020')SELECT * FROM table patients create table doctor (doctor_id VARCHAR(255),name VARCHAR(255),specialization VARCHAR(255),PRIMARY KEY (doctor_id) ); create table test (test_id VARCHAR(255),test_name VARCHAR(255),test_date DATE,test_time TIME,result VARCHAR(255),PRIMARY KEY(test_id)); create table doctor_patient( patient_id VARCHAR(255), doctor_id VARCHAR(255),PRIMARY KEY(patient_id),FOREIGN KEY(doctor_id) REFERENCES doctor(doctor_id) ); create table test_log (test_log_id varchar(255),patient_id VARCHAR(255),test_id VARCHAR(255),doctor_id VARCHAR(255),comments VARCHAR(255),PRIMARY KEY(test_log_id),FOREIGN KEY(test_id) REFERENCES test(test_id),FOREIGN KEY(patient_id) REFERENCES…
Write an anonymous block which updates the .Physician table.(As you can not update the .Physician Table, you will have to create your own table based on the structure and contents of the Physician Table). Use named parameters to get values for Phys_ID, Phys_name, Phys_phone, and Phys_speciality. If the value for Phys_ID is in the Physician Table, Update the values of the remaining columns. If the Phys_ID is not in the Physician Table, INSERT a row into the Physician Table with those values. - Hint: Use variables for each of the columns above and assign a named parameter to each of them. Then use the variable in the rest of the block. - Write a simple driver to test the block with a Phys_ID that is in the Physician Table and a Phys_ID that is not in the Physician Table. Physician Table Phys_ID Phys_Name Phys_Phone Phys_Specialty ----------- ------------------------…
Modify the Job_class column of the EMPLOYEES table so that it allows storing a maximum width of two characters.
Delete the index named ITEM_INDEX3.
12.3 LAB - Create LessonSchedule table with FK constraints Two tables are created: Horse with columns: ID - integer, primary key RegisteredName - variable-length string Student with columns: ID - integer, primary key FirstName - variable-length string LastName - variable-length string Create the LessonSchedule table with columns: HorseID - integer with range 0 to 65 thousand, not NULL, partial primary key, foreign key references Horse(ID) StudentID - integer with range 0 to 65 thousand, foreign key references Student(ID) LessonDateTime - date/time, not NULL, partial primary key If a row is deleted from Horse, the rows with the same horse ID should be deleted from LessonSchedule automatically. If a row is deleted from Student, the same student IDs should be set to NULL in LessonSchedule automatically.
Insert any 5 rows of athletes including your details into the Athletics table you created in the previous Question. The table created previously CREATE TABLE Athletics ( AthleteID int NOT NULL First_name varchar(255) NOT NULL, Last_name varchar(255) NOT NULL, DOB DATE NOT NULL, SportsCode INT, Date_Last_event DATE, PRIMARY KEY (ID) ); varchar(255) use for define string column, int stand for integer field etc.