Create the front view of the sketch of the spur wheel (hand written)
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- This solution is incomplete. What about the answers to the following: d) Diameter of wheel in metres.e) Rotative speed in rpm if peripheral speed is 0.45√2gh.f) Specific speed of turbine in rpm.5 “winpgynba uy 514901 1 001 AU YOI J0j A SITFIOM o1 QurwINAGA natural feed journal bearing of diameter 50mm and length 50mm operating at 20rev/s. Carries a load of 2KN. The lubricant used has a viscosity of 20MPa. The radial clearance is 50um. The Sommerfeld number for the bearing?
- Two mating gears of 20 and 50 teeth of 20° pressure angle has path of contact equal to 35 mm What will be the arc of contact, (cos20 = 0.9397, tan 20°= 0.36397)Question (1): (i) If the angular speed is 20 rad/s and the wind velocity is 10 m/s for a rotor diameter of 25 cm the tip speed will be? (ii) If the clearnes index is 0.352 and the monthly average daily extraterrstrial raditaion is 2800 KJ/m day. Find the global raditaion Need answer within 10 mins.Two spur gears transmit 36kW with a velocity ratio of 2:1. The speed of the smaller driving gear is 100rpm. The centre distance between the shafts is to be as near as possible to 920mm. If m=10 and all-21MPa, determine a) Diameter of the shafts b)PCD for each wheel c)Number of teeth on each wheel d) Actual centre distance [ e) Width of the teeth
- Based on the CNC program below, identify 1)what machine it is (lathe/mill) ? 2)is the coolant used? 3)Any pocket/holes drilling? and if yes how many? 4)How many tool(s) is/are used? N1 G90 G17 G40 G80 G00 N108 M06 T1 (1/4) N110 (F-contour) N112 G00 G54 G90 X0.8937 Y-2.0181 S6000 M03 N114 G43 H1 Z5. N116 Z1. N118 Z0.1 N120 G01 Z0. F30. N122 G03 X0.9302 Y-2.262 Z-0.0007 I0.2488 J-0.0875 F60. N124 G02 X0.9927 Y-2.4845 Z-0.0012 I-0.2631 J-0.1939 N126 G03 X0.9927 Y-2.7716 Z-0.002 I1.6354 J-0.1436 N128 G02 X0.9302 Y-2.9941 Z-0.0026 I-0.3256 J-0.0286 N130 G03 X0.8937 Y-3.2381 Z-0.0032 I0.2123 J-0.1565 N132 X2.0181 Y-4.3624 Z-0.0074 I1.7344 J0.61 N134 X2.262 Y-4.3259 Z-0.008 I0.0875 J0.2488 N136 G02 X2.4845 Y-4.2634 Z-0.0086 I0.1939 J-0.2631 N138 G03 X2.7716 Y-4.2634 Z-0.0094 I0.1436 J1.6354 N140 G02 X2.9941 Y-4.3259 Z-0.01 I0.0286 J-0.3256 N142 G03 X3.2381 Y-4.3624 Z-0.0106 I0.1565 J0.2123 N144 X4.3624 Y-3.2381 Z-0.0148 I-0.61 J1.7344 N146 X4.3259 Y-2.9941 Z-0.0154 I-0.2488…According to the data below, determine the life of FAG 6213 single row deep groove ball bearing to be used in the bearing of the rotary axis in hours. spindle speed = 2000 rpmloads: vertical radial:1600N horizontal radial:3600N axial: 1000 NBEARING FEATURES: NUMBER OF STATIC LOAD: 41.5 KN DYNAMIC LOAD NUMBER: 60KNa steam engine runs at 150rpm. its turning moment diagram gave the areas in mm2 taken in order above and below the mean torque line is 500,250,270,390,190,340,270,250, the scale for turning moment is 1mm=500mnm, 1mm=5’ if the fluctuation of speed is not to exceed +or-1.5% of mean, determine a suitable diameter and cross-section of the rim of flywheel with axial dimension equal to 1.5times the radial dimension. the hoop stress is limited to 3mpa and the density of material of flywheel is 7500kg/m3.