Create your own 2-D list with at-least 5 students and their grades in 5 subjects like the example above. Write a nested for/while loop that would use find the total of 5 subjects for each student and stores that into a sepearate list. Display the Total for each student.
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NEED HELP WITH 2-D list. (PYTHON)
For e.g., the following is another example of 2-D multidimensional list. Each row contains student name followed by their grades in 5 subjects:
students = [ ['Anna', 98.5, 77.5, 89, 93.5, 85.5],To access, a specific row, you would use students[row_number][column_number].
- students[0][0] would print 'Anna'
- students[0][1] would print 98.5
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Create your own 2-D list with at-least 5 students and their grades in 5 subjects like the example above.
-
Write a nested for/while loop that would use find the total of 5 subjects for each student and stores that into a sepearate list.
-
Display the Total for each student.
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- Suppose you have a sitting arrangement of the students of the final exam in a list. The list contains the last two digits of their roll number. sitting_list=[10,30,20,70,11,15,22,16,58,100,12,56,70,80] Now you want to organize the sitting arrangement. You decided to sort all the students in the even indices into ascending order and all the students in the odd indices into descending order. So write a python program that organizes the list for you the way you decided. Sample Output[10, 100, 11, 80, 12, 70, 20, 56, 22, 30, 58, 16, 70, 15]Answer the given question with a proper explanation and step-by-step solution. Write in Java: Write a menu-driven program to illustrate the use of a linked list. The entries will only consist of integer number keys (values). The program should implement the following options in order: • Insert- insert a key into a list- not allowing duplicate integers. • Delete- delete a key from the list. • Search- finds or does not find a particular key in the list. • Print- prints the list graphically in horizontal form. If the list is empty output- "Nothing to print". • Size- count of all the keys in the list. • Sort- sorts the keys in the list in ascending order. • Reverse- reverses the order of the keys in the list • Rotate- moves the key at the front of the list to the end of the list. If the list has 0 or 1 elements it should have no effect on the list. • Shift- rearranges the keys of a list by moving to the end of the list all values that are in odd number positions (indexes) and otherwise…Python Implement a singly linked list with the following functions: - add_head(e) - add_tail(e) - find_3rd_to_last() - returns element located at third-to-last in the list - reverse() - reveres the linked list, note, this is not just printing elements in reverse order, this is actually reversing the list
- In python, remove_from_list(my_list, indices): Takes two lists as input. Creates a new list from the first input list by removing the elements at indices given by the integers in the second input list, then return the new list. The indices in the second input list may have any order. For example, if the first input list is [4, 8, 12, 16], and the second input list is [0, 2], then the new list returned from the function should have the 4 and the 12 removed, because they were at indices 0 and 2 of the original list. Note: You do not need to consider negative indices for this function. >>> remove_from_list(['abc', 'def', 'ghi'], [1]) ['abc', 'ghi'] >>> strs = ['The', 'quick', 'brown', 'fox'] >>> remove_from_list(strs, [0, 3]) ['quick', 'brown'] >>> strs ['The', 'quick', 'brown', 'fox'] # original list is unchanged >>> remove_from_list(['The', 'quick', 'brown', 'fox'], [3, 0]) ['quick', 'brown']For this discussion consider the following: What is a list used for in Python? When might you use a list? Give a real-world example you make up, not something from your book or the Internet) Does the order of items in a list matter? Why or why not? (That means explain your answer do not just answer ‘yes’ or ‘no’). Provide examples to support if the order matters or not.[Python] [you can use modules if necessary] say I have a list consist of pairs order = [ 'A-1', 'A-2', 'A-3', 'A-4', 'B-1', 'B-2', 'B-3', 'B-4', 'C-1', 'C-2', 'C-3', 'C-4', 'D-1', 'D-2', 'D-3', 'D-4', 'E-1', 'E-2', 'E-3', 'E-4', 'F-1', 'F-2', 'F-3', 'F-4', 'G-1', 'G-2', 'G-3', 'G-4' Let say the the letters are 'let' and the numbers are 'num'. notice how there are 7 let each paired with 4 num. 1.) How do I make a code that prints only the third and the first pair from the list above? *include notes in your code* This is the expected output: A-3, A-1, B-3, B-1, C-3, C-1, D-3, D-1, E-3, E-1, F-3, F-1, G-3, G-1
- Write a program where 2 linked lists have ben create and now the main task is to merge the linked lists and display the merged list. For example, merging lists {1, 2, 3} and {7, 13, 1} should yield {1, 7, 2, 13, 3, 1} Note: the above mentioned task is to be performed using doubly linked list and in C++Python: Given the lists, Ist1 and Ist2, create a new sorted list consisting of all the elements of Ist1 that also appears in Ist2. For example, if Ist1 is 4, 3, 2, 6, 2] and Ist2 is [1, 2, 4]; then the new list. would be [2, 2, 4]. Note that duplicate elements in Ist1 that appear in Ist2 are also duplicated in the new list. Associate the new list with the variable new_list, and don't forget to. sort the new list.use python and EXPLAIN what you did Suppose you have the following animal names in a list: cat, dog,mouse, hamster. Write a code that prints the first letter, the last letter, andthe length of each animal’s name. Print out all the animal names that havea length greater than 3. and then Write a program that counts the number of aletter that appears in the list (i.e. the frequency of the letter).
- Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list Develop your solution as follows: First copy the nodes of the current list (self) Create a new list with the copied nodes Loop through the nodes of the new list checking the value field If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L): def clone(self): def clone_node(node): return <... YOUR CODE HERE ...> r = <... YOUR CODE HERE...> return r return L4_class(*args,**kwargs)In PYTHON, write a program that reads elements from a list, where each element from the list is a list with three values. Call the function defined in part 1 with the 3 values as arguments in order and print the returning value.Test your code with the list:"numbers=[[3, 5, 4], [7, 4, 3], [2, 3, 1]]" The functions defined in part 1 were: def greater(a, b, c): if a > b: return c elif a > c: return b else: return aThe function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
