Give me correct options with explanation please temperatureType II heat pump cycle can convert a portion of the waste heat energy into a heat transfer out of the cycle at theSelect one:O a. moderate and lowestb highestO c lowestO d. moderateIn the absorber and evaporator of LIBR-H2O absorption system, low heat flux leads toSelect one:Oa. higher vapor velocities and small components size.b. higher vapor velocities and large components size.C. lower vapor velocities and large components size.O d. lower vapor velocities and small components size.

Answered: ct one: a. moderate and lowest b.…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Thermodynamics To the compressor of a vapor compression refrigeration cycle with an adiabatic redemption of 78%, refrigerant 134a enters as saturated vapor at 20 psia. Saturated liquid enters expansion valve at 160 psia. For the 5 Ton refrigeration equipment, Determine:a) The temperature of the fluid leaving the compressor, in ºF,b) the COP,c) Input power to the compressor in hp.
A man has an engine working in an ideal Ericsson engine with the gas helium as the working fluid. This engine operates between temperature limits of 305.37 K and 2540 oF and pressure limits of 1292.52 Torr and 13.605 atm. Assuming a mass flow rate of 6.3636 kg/s, determine the heat transfer in the regenerator in Btu/s. a. 72,875 b. 62,875 c. 52,875 d. 42,875
The evaporator and condenser temperatures are -20°C and 35°C, respectively, in an ammonia simple saturation cycle. The method will be used to produce 12,500kg of ice at -15°C in 32 hours from water at 25°C. Assuming that 25 percent of the heat absorbed from the water is lost. Ice has a specific heat of 2.094Kj/kg-K, while fusion has a heat of 335kj/kg. Determine the: a) Total Heat b) Mass flow rate
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A simple vapor compression refrigeration cycle using R-134a operates at a condensingtemperature of 30oC and an evaporator temperature of -10oC. For a cooling capacity of(10 + 0.1×72) tons, determine,(i) COP,(ii) the power required to drive the compressor in kW.
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Step: Evaluate the performance of Refrigerator 2.Refrigerator 2 is a refrigerator that operates as an ideal vapor refrigeration cycle, and uses theSame refrigerant and evaporation and condensing temperatures as Refrigerator 1.In Cooler 2, the working fluid must be admitted by the compressor only in the form of vaporsaturated, and must leave the compressor in the form of superheated steam with enthalpy equal to 1640 kJ/kg.Differently from Refrigerator 1, the cycle operates with an expansion valve (isenthalpic process).For this 2nd step, you must determine the following design parameters:a) The rate of cooling and the rate of heat rejection in the condenser.b) The power of the compressor;c) The COP of the cycle.For the energy balance, make the following considerations:- Permanent regime;- Variation of kinetic and potential energy are negligible;- Compressor and expansion valve operate adiabatically;- Evaporation and condensation steps do not involve work. Please, make it typeable,…
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ct one: a. moderate and lowest b. highest