Current Attempt in Progress Water is to be pumped from the large tank shown in the figure below with an exit velocity V₂ of 5.6 m/s. It was determined that the original pump (pump 1) that supplies 1 kW of power to the water did not produce the desired velocity. Hence, it is proposed that an additional pump (pump 2) be installed as indicated to increase the flowrate to the desired value. How much power must pump 2 add to the water? The head loss for this flow is h₁ = 240Q², where h₁ is in m when Q is in m³/s. Assume z = 2.3 m, A₁ = 0.04 m², A₂ = 0.02 m². W. pump2 = Nozzle area 4₂ Pump for #2 kW Pipe area A₁ Pump #1

Sustainable Energy
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Author:DUNLAP, Richard A.
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Chapter14: Ocean Thermal Energy Conversion And Ocean Salinity Gradient Energy
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Current Attempt in Progress
Water is to be pumped from the large tank shown in the figure below with an exit velocity V₂ of 5.6 m/s. It was determined that the
original pump (pump 1) that supplies 1 kW of power to the water did not produce the desired velocity. Hence, it is proposed that an
additional pump (pump 2) be installed as indicated to increase the flowrate to the desired value. How much power must pump 2 add to
the water? The head loss for this flow is h = 240Q2, where he is in m when Q is in m³/s.
Assume z = 2.3 m, A₁ = 0.04 m², A₂ = 0.02 m².
W
pump2 =
kW
V₂
Nozzle area A₂
Pump
#2
Pipe area A₁
Pump
#1
-
Transcribed Image Text:Current Attempt in Progress Water is to be pumped from the large tank shown in the figure below with an exit velocity V₂ of 5.6 m/s. It was determined that the original pump (pump 1) that supplies 1 kW of power to the water did not produce the desired velocity. Hence, it is proposed that an additional pump (pump 2) be installed as indicated to increase the flowrate to the desired value. How much power must pump 2 add to the water? The head loss for this flow is h = 240Q2, where he is in m when Q is in m³/s. Assume z = 2.3 m, A₁ = 0.04 m², A₂ = 0.02 m². W pump2 = kW V₂ Nozzle area A₂ Pump #2 Pipe area A₁ Pump #1 -
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