(D² – 3D – 4)y = 0 is ° y = C,e** + C,e* " y = C,e** + C,e* 4х 4x -X -4x ° y = C,e** + C,e* y = C,e* + C,e* -x -4x

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
icon
Related questions
Question

The general solution of 

(D² – 3D – 4)y = 0
is
° y = C,e** + C,e*
" y = C,e** + C,e*
4х
4x
-X
-4x
° y = C,e** + C,e*
y = C,e* + C,e*
-x
-4x
Transcribed Image Text:(D² – 3D – 4)y = 0 is ° y = C,e** + C,e* " y = C,e** + C,e* 4х 4x -X -4x ° y = C,e** + C,e* y = C,e* + C,e* -x -4x
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer