d (6) 는 (cotx) dx II

Q: 11. V4-V4-x dx

A:

Q: 9-x2 x dx

A: ∫9-x2x2dx=∫cot2udu=∫ -1+csc2udu=-∫ 1du+∫csc2udu=-u-cotuSubstitute back…

Q: 5. Evaluate: (а) ( 5х* -х-4) dx (b) f( 2x +4)(3x + 6)dx

A: 5. (a) We will evaluate the integral ∫5x2-x-4dx

Q: differenti en y(2) =

A:

Q: ƒ7 In ()dx if sec¹ (3x) dx

A: Integration by parts: ∫f(x)·g(x) dx = f(x)·∫g(x) dx - ∫ddxf(x)·∫g(x) dx dx

Q: 9. dx 5-4x-x²

A: As per our guideline we are supposed to be answer only one question you can repost other question in…

Q: sec4 dx

A: The integral is . Let . Differentiating both sides.

Q: Ул4 — dx 2x2 + 1 3,

A:

Q: 14) fx In(4x) dx

A:

Q: cln3 Sng tanh(x) sech³(x) dx JIn2

A: To find: ∫ln2ln3tanhxsech3xdx

Q: VALUATE xx4 dX 3

A: to find:- integration of the given function. *concept:- let,  x^3+4 = t.

Q: 1 + cosh 2x 9. cosh² x 2

A: To prove the identity

Q: Find 1 SC + sec²6x + 9)dx: e3x None -3x tanbx + 9 x + c 6 -3 -3x tan3x + 9 x + c 6 -3 e-3x tanbx +9…

A: We can solve the given integral .

Q: -2 Evaluate (5х — 2) dx -6

A:

Q: 20. [2z°e*= dz

A: According to our guidelines we can answer on three subparts, or first question and rest can be…

Q: -dx +5 3.

A: integarting   let subsitution  methood

Q: Evaluate 1 foto dx. 6 + e-4x -dx 1 6+e - 4x = + C

A: Given : ∫16+e-4xdx To find: Evaluate the given integral

Q: ди + 2и ду %3D dx2

A: Given PDE is

Q: Integrate dx/(2x-5)^4

A: Given integral is I=∫1(2x-5)4dx Let us substitute  u=2x-5du=2dx Integral is transformed using above…

Q: Number 20

A: To evaluate

Q: S 36x2+25 - dx

A:

Q: Calculate dx2 y = 2x0.4 – 3x d²y dx2

A:

Q: 2х + 1 бх2 + 23х — 9 dx х3 + 2х2 — 3х Ja- 2)(x – 3)² dx

A:

Q: 4. S Vtanx sec6x dx

A:

Q: = vt – 2. a²y y = t2 – 3' dx²

A: The solution are next step

Q: 4 dx x2 4x2 - -- x2

A:

Q: 7. CIn (x)² dx

A: Given data:     The given integral is:   The given integral can be written as, Apply integration…

Q: 5x - 3 √(x+ - 4x³ + 14x² - 20x + 25) - - dx

A:

Q: Vtan(7x) sec?(7x) dx

A: Given query is to find the integral of the expression.

Q: Sx Vx + 10 dx

A:

Q: cIn2 cln5 e2r+y dy dx

A: I am going to solve the given problem by using some simple calculus to get the required result.

Q: Evaluate: ₂₁ (4x²y - z³) dz dy dx

A: We can solve this as follows:

Q: dx Vx²+9

A:

Q: JA 1 dx. /4-

A: ∫14-x2dxFormula∫11-x2dx=sin-1(x)+C

Q: Зх +5 .-4x+9 - dx Зx? — 4х +9

A:

Q: Right tria

A: In the given right angled triangle △JKLwe have, JK = 4 JL = 6 We have to find the measure of ∠J.

Q: Se 3+2tan4x sec²4x(etan4x + 6)°dx

A: LetI=∫ e3+2tan4xsec24xetan4x+69dxI=∫ e3e2tan4xsec24xetan4x+69dxI=∫…

Q: dx Ji slx+4) 1 (r+4

A:

Q: dx Integrate: /16-9x²

A: Answer and explanation is given below...

Q: \ dx lox-x+15 (2X-1)(x4)

A: use partial fraction  ...................(1) ...................(2) take x=1/2 ..............put…

Q: dx J-25a2 1–25x² -25x2 8.

A: The objective is to evaluate the integration.

Q: sec x =dx Vtan x 3 8. 4

A:

Q: 9. -dx 5 Vx – 5

A:

Q: 3x dx S V4 - х

A: We have to evaluate the integral: ∫3x dx4-x Solving by substitution method. Assuming, t2=4-x…

Q: Integrate. 3. .2 CSC X+ sc² dx

A: Given,           ∫csc2x+3x-x53dx

Q: Vsin² 2x dx =?

A: Given ∫02πsin2 (2x) dx Remember sin2 (2x) is always positive. Thus, sin2 (2x) should be positive for…

Q: 1.ſ(8x³ − 6x² + 12x − - -9)dx

A: Solve the integration

Q: Sse sech²xtanh²x dx 2.

A:

Q: 2) dx 4. - |

A: We can use method of substitution in order to solve the problem problem.