id like to see part d plz! 1. This question concerns the motion of a crate being pulled across ahorizontal floor by a rope. In the diagram below, the mass of the crate ism, the coefficient of kinetic friction between the crate and the floor is µ,and the tension in the rope is Fr.rope(a) Draw and label all of the forces acting on the crate.(b) Compute the normal force acting on the crate in terms of m, Fr , 0,and g.(c) Compute the acceleration of the crate in terms of m, Fr , 0, µ, and g.(d) Assume that the magnitude of the tension in the rope is fixed but thatthe angle may be varied. For what value of 0 would the resultinghorizontal acceleration of the crate be maximized?

Given information: A box of mass “m” is pulled by a rope inclined at an angle theta w.r.t…

Answered: (d) Assume that the magnitude of the…

(d) Assume that the magnitude of the tension in the rope is fixed but that the angle may be varied. For what value of 0 would the resulting horizontal acceleration of the crate be maximized?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter1: A Physics Toolkit

Section: Chapter Questions

Problem 7STP

See similar textbooks

Similar questions

Which of the following statements is accurate? (a) Mass and weight are the same thing expressed In different units. (b) If an object has no weight, it must have no mass. (c) If the weight of an object vanes, so must the mass. (d) Mass and inertia are different concepts. (e) Weight is always proportional to mass.
A force F1, of magnitude 6.00 units acts on an object at the origin in a direction = 30.0 above the positive x-axis (Fig. P3.8). A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2?. Figure P3.8
A force is a quantity that is ___ of producing motion or a change in motion. (3.1)
The helicopter view in Figure P1.70 shows two people pulling on a stubborn mule. Find (a) the single force that is equivalent to the two forces shown and (b) the force a third person would have to exert on the mule to make the net force equal to zero. The forces are measured in units of newtons (N). Figure P1.70
A person in a kayak starts paddling, and it accelerates from 0 to 0.703 m/s in a distance of 0.307 m. If the combined mass of the person and the kayak is 61.3 kg, what is the magnitude of the net force acting on the kayak? Number Type your answer here Units Choose your answer here
As you will see in a later chapter, forces are vector quantities, and the total force on an object is the vector sum of all forces acting on it. In the figure below, a forceF1of magnitude 6.40 units acts on a crate at the origin in a direction θ = 28.0° above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the crate in the direction of the positive y-axis. Find graphically the magnitude and direction (in degrees counterclockwise from the +x-axis) of the resultant force F1 + F2. magnitude units direction° counterclockwise from the +x-axis
A horizontal force of magnitude F = 56.2 N pushes on a block of mass m = 5.87 kg. The block is on a frictionless incline that makes and angle θ = 33.9 degrees with horizontal.Write an expression for the acceleration ax of the block, taking up the ramp to be the positive x direction. Express your answer in terms of F, m, θ, and g (9.80 m/s2). What is the acceleration of the block in units of meters per seconds squared?
Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in (Figure 1) has a mass m=10kg and is being pulled by a force F on a table with coefficient of static friction μs=0.3. Four forces act on it: The applied force F (directed θ=30 above the horizontal). The force of gravity Fg=mg (directly down, where g=9.8m/s2). The normal force N (directly up). The force of static friction fsfs (directly left, opposing any potential motion). If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsNfs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: Fcosθ−μsN=0 Fsinθ+N−mg=0 In order to find the magnitude of force FF, we have to solve a system of two equations with both FF and the…
You pull on a crate using a rope as in (Figure 1), except the rope is at an angle of 20.0 ∘∘ above the horizontal. The weight of the crate is 245 NN, and the coefficient of kinetic friction between the crate and the floor is 0.270. What must be the tension in the rope to make the crate move at a constant velocity? Express your answer with the appropriate units.
A book with mass = 2.25 kg rests on the surface of a bar. The coefficient of static friction between the book and the par us=0.71 and the coefficient of kinetic friction is uk=0.44.What would be the expression for Fm the minimum force required to move the book on the surface of the bar and how is this solved numerically for the magnitude of the force Fm in Newtons?
Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in (Figure 1) has a mass m=10kg and is being pulled by a force F on a table with coefficient of static friction μs=0.3. Four forces act on it: The applied force FF (directed θ=30∘above the horizontal). The force of gravity Fg=mgFg=mg (directly down, where g=9.8m/s2). The normal force N (directly up). The force of static friction fs (directly left, opposing any potential motion). If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsN, we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: Fcosθ−μsN=0 Fsinθ+N−mg=0 In order to find the magnitude of force F, we have to solve a system of two equations with both F and the…
A boy slides down a hill on a sled (total mass of 42 kg) and coasts onto a flat plain with a speed of 6.1 m/s. Friction between the sled and the snow exerts an average force of magnitude 39 N on the sled. How far (in m) does the sled travel before stopping? (Note: First, find the acceleration of the boy using Unit Two material, then use this to compute the distance using Unit One material.)